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3 years ago

Write an equation for the line that is parallel to the given line and that passes through the given point.

Mathematics

2 answers:

SSSSS [86.1K]3 years ago

5 0

Answer:

the answer is B. y equals five halves x minus 14

Step-by-step explanation:

hope it helps

tresset_1 [31]3 years ago

4 0

Answer:

The correct option is B.

Step-by-step explanation:

The slope intercept form of a line is

$y=mx+b$

where, m is slope and b is y-intercept.

The given equation is

$y=\frac{5}{2}x-10$

It means the slope of the line is 5/2 and y-intercept is -10.

The slope of two parallel lines is same. So, the slope of required line is 5/2.

The equation of required line is

$y=\frac{5}{2}x+b$

It is given that the line passes through the point (-6,-29).

$(-29)=\frac{5}{2}(-6)+b$

$-29=-15+b$

$-29+15=+b$

$-14=b$

The y-intercept of required line is -14. So the equation of required line is

$y=\frac{5}{2}x-14$

Therefore the correct option is B.

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I NEED HELP

creativ13 [48]

Answer:

1). (x - 4 = 13)

2). (r + 17 = 51)

3). (7/9x =28)

4). (2/3x = 2)

5). { 3(x-2) = -9 }

6). (x -1.75 = 8.85)

7). Natalie buys organic almonds priced at $77 from the grocery store. How much did

she pay the cashier, if she received $23 in change?

Step-by-step explanation:

1. add 4 on both sides and it will be x=17

2. subtract 17 on both sides and it will be x= 34

3. multiply 9/7 on both sides and it will be x= 257/7 then you divide 257 by 7 then the final answer will be x= 36

4. multiply 3/2 on both sides and it will be x=6/2 then you divide 6 from 2 and the finial answer will be x= 3

5. you will distribute 3 into x and 2 and you will be 3x-6=-9 then you will add 6 on both sides so you will get 3x=3 and then divide 3 on both side so you will get x=1

6. add 1.75 on both sides so x= 10.6

7. the equation will be 23 +x = 77 so first you will subtract 23 on both sides and x will equal 54 so Natalie paid $54

6 0

3 years ago

Read 2 more answers

Write each percent increase or decrease as a percentage of the initial amount. The first one is done for you.

olya-2409 [2.1K]

Answer:

This amount of sunny days this year is 75% of the amount of sunny days last year.

Step-by-step explanation:

5 0

3 years ago

I don't get this please help me! it's only 8th grade math. thanks!(:

solmaris [256]

The time × 1.5=the distance
so 5×1.5=7.5
10×1.5=15
20×1.5=30
im a 7th grader doing 8th grade math.. just think

8 0

3 years ago

1. Let the test statistics Z have a standard normal distribution when H0 is true. Find the p-value for each of the following sit

Nonamiya [84]

Answer:

1 a $p -value = 0.030054$

1b $p -value = 0.0029798$

1c $p -value = 0.0039768$

2a $p-value = 0.00099966$

2b $p-value = 0.00999706$

2c $p-value = 0.0654412$

Step-by-step explanation:

Considering question a

The alternative hypothesis is H1:μ>μ0

The test statistics is z =1.88

Generally from the z-table the probability of z =1.88 for a right tailed test is

$p -value = P(Z > 1.88) = 0.030054$

Considering question b

The alternative hypothesis is H1:μ<μ0

The test statistics is z=−2.75

Generally from the z-table the probability of z=−2.75 for a left tailed test is

$p -value = P(Z < -2.75) = 0.0029798$

Considering question c

The alternative hypothesis is H1:μ≠μ0

The test statistics is z=2.88

Generally from the z-table the probability of z=2.88 for a right tailed test is

$p -value = P(Z >2.88) = 0.0019884$

Generally the p-value for the two-tailed test is

$p -value = 2 * P(Z >2.88) = 2 * 0.0019884$

=> $p -value = 0.0039768$

Considering question 2a

The alternative hypothesis is H1:μ>μ0

The sample size is n=16

The test statistic is t = 3.733

Generally the degree of freedom is mathematically represented as

$df = n - 1$

=> $df = 16 - 1$

=> $df = 15$

Generally from the t distribution table the probability of t = 3.733 at a degree of freedom of $df = 15$ for a right tailed test is

$p-value = t_{3.733 , 15} = 0.00099966$

Considering question 2b

The alternative hypothesis is H1:μ<μ0

The degree of freedom is df=23

The test statistic is ,t= −2.500

Generally from the t distribution table the probability of t= −2.500 at a degree of freedom of df=23 for a left tailed test is

$p-value = t_{-2.500 , 23} = 0.00999706$

Considering question 2c

The alternative hypothesis is H1:μ≠μ0

The sample size is n= 7

The test statistic is ,t= −2.2500

Generally the degree of freedom is mathematically represented as

$df = n - 1$

=> $df = 7 - 1$

=> $df = 6$

Generally from the t distribution table the probability of t= −2.2500 at a degree of freedom of $df = 6$ for a left tailed test is

$t_{-2.2500 , 6} = 0.03272060$

Generally the p-value for t= −2.2500 for a two tailed test is

$p-value = 2 * 0.03272060 = 0.0654412$

4 0

3 years ago

2. Simplify: 2xy + 10x2 - 9xy

Hatshy [7]

The answer is letter D

3 0

3 years ago