1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Luba_88 [7]
2 years ago
6

Write an equation for the line that is parallel to the given line and that passes through the given point.

Mathematics
2 answers:
SSSSS [86.1K]2 years ago
5 0

Answer:

the answer is  B. y equals five halves x minus 14

Step-by-step explanation:

hope it helps

tresset_1 [31]2 years ago
4 0

Answer:

The correct option is B.

Step-by-step explanation:

The slope intercept form of a line is

y=mx+b

where, m is slope and b is y-intercept.

The given equation is

y=\frac{5}{2}x-10

It means the slope of the line is 5/2 and y-intercept is -10.

The slope of two parallel lines is same. So, the slope of required line is 5/2.

The equation of required line is

y=\frac{5}{2}x+b

It is given that the line passes through the point (-6,-29).

(-29)=\frac{5}{2}(-6)+b

-29=-15+b

-29+15=+b

-14=b

The y-intercept of required line is -14. So the equation of required line is

y=\frac{5}{2}x-14

Therefore the correct option is B.

You might be interested in
Express your answer in scientific notation.<br> 1.8x 10^-2 – 3.9 x 10^-3 =
DIA [1.3K]

Answer:

1.41 x 10^-2

Step-by-step explanation:

1.8 x 10^-2 - 3.9 x 10^-33 = 18 x 10^-3 - 3.9 x 10^-3

                                        = (18-3.9) x 10^-3

                                        = 14.1 x 10^-3

                                        = 1.41 x 10^-2

Comment below if you have any questions! If you could mark this answer as the brainliest I would appreciate it!

4 0
2 years ago
Solve this question please what is 2 +2
kkurt [141]

Answer:

4

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
The length of a rectangular poster is 9 more inches than two times its width. The area of the poster is 161 square inches. Solve
irinina [24]

Answer:

<u>Width = 7 inches</u>

<u>Length = 23 inches</u>

Step-by-step explanation:

Let :

  • length = 2x + 9
  • width = x

Equating to area :

  • (2x + 9)(x) = 161
  • 2x² + 9x = 161
  • 2x² + 9x - 161 = 0
  • 2x² - 14x + 23x - 161 = 0
  • 2x(x - 7) + 23(x - 7) = 0
  • x - 7 = 0
  • x = 7

Dimensions are :

  • <u>Width = 7 inches</u>
  • Length = 2(7) + 9
  • <u>Length = 23 inches</u>
8 0
2 years ago
Read 2 more answers
Given: △ACD, m∠BCA = 60° CB ⊥ AD , m∠BDC = 45° AC = 10 cm. Find: BC and DC
neonofarm [45]

Answer:

See if this will help,

https://www.pmschools.org/site/handlers/filedownload.ashx?moduleinstanceid=701&dataid=3612&FileName=2015%20triangle%20proofs%20answers.pdf



8 0
3 years ago
PLEASE HURRY!!! AB = 20 cm, m∠A = 30° , and $m∠C = 45° . Express the number of centimeters in the length of BC in simplest radic
MrRissso [65]
Using the Sine Rule:-

20 /sin 45 =  BC / sin 30

BC = 20 sin 30 / sin45

  = 20 * 1/2  /  1 / sqrt2
  = 20 * 1/2 * sqrt2
=  10 sqrt2   answer
3 0
3 years ago
Other questions:
  • Kelsi's mom, Sue, is 8 times as old as Kelsi. In 10 years , Sue will be 3 times as old as Kelsi. How old are Kelsi and Sue now?
    14·2 answers
  • Help plzzzzzzzzzzzzzzzzzzzzzz
    12·1 answer
  • If f(x)=x^2 and g(x)=1÷2x+3 find g(f(-1))
    13·1 answer
  • A pilot in an apache rescue helicopter, at an altitude of 1200 feet, spots his two soldiers on the ground. the angles of depress
    9·1 answer
  • What expression is equivalent to 15 + 80?
    15·2 answers
  • A problem states that Ursula earns $9 per hour. To write an expression that tells how much money Ursula earns for h hours, Joshu
    10·1 answer
  • Tanya is considering obtaining a loan. Which benefit will Tanya receive if she makes a down payment when she obtains the loan?
    6·1 answer
  • Is -14 greater than less than or equal to -3
    7·1 answer
  • Which expression is equivalent to 8r+16
    8·1 answer
  • 3x -4 = x -8 equation ​
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!