Complementary angles ⇒ the angles add up to 90°
∠A and ∠B are complementary ⇒ ∠A + ∠B = 90°
∠A + ∠B = 90°
Plug in the values for ∠A and ∠B:
(3x - 8) + (5x + 10) = 90
Open the brackets:
3x - 8 + 5x + 10 = 90
Combine like terms:
8x + 2 = 90
Subtract 2 from both sides:
8x = 88
Divide both sides by 8:
x = 11
Answer: x = 11
Answer: 2
Step-by-step explanation:
Answer:
10.20% probability that a randomly chosen book is more than 20.2 mm thick
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean and standard deviation , the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
250 sheets, each sheet has mean 0.08 mm and standard deviation 0.01 mm.
So for the book.
What is the probability that a randomly chosen book is more than 20.2 mm thick (not including the covers)
This is 1 subtracted by the pvalue of Z when X = 20.2. So
has a pvalue of 0.8980
1 - 0.8980 = 0.1020
10.20% probability that a randomly chosen book is more than 20.2 mm thick
Answer:
755,160 ways
Explanation:
We're told that 31 cars are in a race.
Considering the order in which the cars can finish in the top 4 positions, any of the 31 cars can finish in the first position, any of the remaining 30 cars can finish in the second position, any of the remaining 29 cars can finish in the third position and any of the remaining 28 cars can finish in the fourth position, so the different numbers of ways can be determined as seen below;
C = 5/9(F - 32) = 5/9(94 - 32) = 5/9(62) = 34 4/9 C