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3 years ago

Which coefficients correctly balance the formula equation CaCo3(s) CaCo3+CO2(g)? a. 1, 1, 1 c. 2, 6, 3 b. 1, 3, 1 d. 3, 1, 2

1 answer:

8 0

Answer: option a: 1,1,1

Explanation:

1) The chemical equation given is wrong. This is the right chemical equation

CaCO3(s) → CaO(s) + CO2(g)?

2) To balance you start by counting the number of atoms of each element on both sides

element number of atoms conclusion
reactant side product side

Ca 1 1 balanced

C 1 1 balanced

O 3 1+2 = 3 balanced

3) Therefore all the elements are balanced and the coefficients are 1, 1, and 1.

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Sodium hydroxide reacts with aluminum and water to produce hydrogen gas: 2 Al(s) + 2 NaOH(aq) + 6 H2O(l) → 2 NaAl(OH)4(aq) + 3 H

lianna [129]

Answer:

The mass of hydrogen gas formed is 0.205 grams

Explanation:

Step 1: Data given

Mass of 1.83 grams of Al

Mass of NaOH = 4.30 grams

Molar mass of Al = 26.98 g/mol

Molar mass of NaOH = 40 g/mol

Step 2: The balanced equation:

2 Al(s) + 2 NaOH(aq) + 6 H2O(l) → 2 NaAl(OH)4(aq) + 3 H2(g)

Step 3: Calculate moles of Al

Moles Al = mass Al / Molar mass Al

Moles Al = 1.83 grams / 26.98 g/mol

Moles Al = 0.0678 moles

Step 4: Calculate moles of NaOH

Moles NaOH = 4.30 grams / 40 g/mol

Moles NaOH = 0.1075 moles

Step 5: Calculate limiting reactant

For 2 moles of Al, we need 2 moles of NaOH

Aluminium is the limiting reactant. It will completely be consumed ( 0.0678 moles)

NaOH is in excess. There will react 0.0678 moles

There will remain 0.1075 - 0.0678 = 0.0397 moles

Step 6: Calculate moles of hydrogen

For 2 moles of Al, we need 2 moles of NaOH, to produce 3 moles of hydrogen

For 0.0678 moles of Al, there is produced 0.0678 *3/2 = 0.1017 moles of H2

Step 7: Calculate mass of H2

Mass of H2 = Moles H2 * Molar mass of H2

Mass of H2 = 0.1017 moles * 2.02 g/mol

Mass of H2 = 0.205 grams

The mass of hydrogen gas formed is 0.205 grams

6 0

3 years ago

What is the molarity of a solution containing 8.9 g of NaOH in 550. mL of NaOH solution?

bulgar [2K]

Answer:

0.4 M

Explanation:

Molarity is defined as moles of solute, which in your case is sodium hydroxide,

NaOH

, divided by liters of solution.

molarity

moles of solute

liters of solution

Notice that the problem provides you with the volume of the solution, but that the volume is expressed in milliliters,

Moreover, you don't have the number of moles of sodium hydroxide, you just have the mass in grams. So, your strategy here will be to

determine how many moles of sodium hydroxide you have in that many grams

convert the volume of the solution from milliliters to liters

So, to get the number of moles of solute, use sodium hydroxide's molar mass, which tells you what the mass of one mole of sodium hydroxide is.

⋅

1 mole NaOH

40.0

0.175 moles NaOH

The volume of the solution in liters will be

500

⋅

1 L

1000

0.5 L

Therefore, the molarity of the solution will be

0.175 moles

0.5 L

0.35 M

Rounded to one sig fig, the answer will be

0.4 M

Explanation:

6 0

2 years ago

Calculate the frequency of a yellow light with a wavelength of 5.60 x 10-9 m.

Whitepunk [10]

Answer:

Explanation:

8 0

3 years ago

A cell with osmolarity measuring 300 mosm/l is placed in a beaker that contains a nacl solution with osmolarity of 150mosm/l. pr

tia_tia [17]

My hypothesis is the the cell, having a higher osmolarity than the solution of of nacl in the beaker, will have an osmosis reaction releasing into the solution of nacl. This will continue until both cell and solution reach a balance.

5 0

3 years ago

Please help with everything

Vanyuwa [196]

Search the question up on google and it will show up.

5 0

3 years ago