AB = ==> distance between the bottom of the plank; and the wall ===> 3 ft.
C ====> 49 degrees
For letter a, to solve for AC:
AC ==> HYPOTENUSE. The angle C is the OPPOSITE side of AB.
use sine :
sin A ===> opposite/hypotenuse
Solve:
sin 49 ====> 3/AC
AC ====> 3 / sin 49
AC ====> 3.96 ft.
For letter b, to solve for BC:
We are now given with the base (3 ft.); and; the hypotenuse (3.96 ft.) so we can use the Pythagorean theorem:
a^2 + b^2 = c^2
Let:
a ===> AB
b ===> BC
c ===> AC
(AB)^2 + (BC)^2 ===> (AC)^2
3^2 + (BC)^2 ===> (3.96)^2
(BC)^2 ===> (3.96)^2 - 3^2
(BC)^2 ===> 6.6816
sqrt (BC)^2 ===> sqrt 6.6816
Answer: BC ===> 2.58 ft.
Hope that helps!!!! : )
Answer:
64.8
Step-by-step explanation:
Pythagoreon Theroem
a^2 + b^2 = c^2 in this situation it would actually be the opposite, seeing where the "x" is (on a leg) c^2 - b^2 = a^2. First take the square of 67 and 17
67 squared is 4489 and 17 squared is 289 then subtract both results
4489-289 = 4200 take the square root of this number
64.8074 (Round to the tenths 64.8)
Let the position of the airport be A, the point 160 miles north be B, and the point 85 miles east of that (i.e. the location of the plane) be C. Then ABC forms a right-angled triangle.
<span>tan BAC = 85/160 </span>
<span>BAC = arctan (85/160) </span>
<span>= arctan 0.531 (approx.) </span>
<span>= 27.98° (approx.) </span>
<span>So C is N 27.98° E from A. </span>
<span>The plane should fly S 27.98° W to get to the airport.
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.
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I believe it would be C. 40 feet.
Answer:
Angles congruent to ∠8 are ∠1, 4, 5
Step-by-step explanation:
Hope this helps
