Divide: x^10/x^4. thank you very much

1 answer:

7 0

Simple,

you have $\frac{ x^{10} }{ x^{4} }$

This really means that you have...

$\frac{x*x*x*x*x*x*x*x*x*x}{x*x*x*x}$

just cancel out the x's that you have, it's simple...

leaving you $x^{6}$

Thus, your answer.

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Find the values forX, Y, and Z so that all the following statements are true.

kvasek [131]

Answer:

x = -36, y = 6, z = -6

Step-by-step explanation:

The requirement x/z = -z means x = -z².

The requirement x/y = z means x = yz.

These two requirements together mean yz = -z², or y = -z.

The requirements that z/2 and z/3 are integers mean that z is a multiple of 2·3 = 6. The smallest magnitude non-zero multiple is z=-6 (since we also require z < -z).

Using z=-6, we have x = -z² = -36; y = -(-6) = 6.

For some positive integer n, ...

... x = -36n², y = 6n, z = -6n.

8 0

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kow [346]

Answer:

center of mass

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