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4 years ago

14

Divide: x^10/x^4. thank you very much

1 answer:

nata0808 [166]4 years ago

7 0

Simple,

you have $\frac{ x^{10} }{ x^{4} }$

This really means that you have...

$\frac{x*x*x*x*x*x*x*x*x*x}{x*x*x*x}$

just cancel out the x's that you have, it's simple...

leaving you $x^{6}$

Thus, your answer.

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Solve the following absolute value equation.

dolphi86 [110]

Hey there!

$|\displaystyle\frac{x-1}{2} |=7$

Let's say that x-1 is negative:

$\displaystyle\frac{-x+1}{2} =7$

The first step is to multiply both sides by 2:

$\text{-x+1=14}$

Now, move 1 to the right, using the opposite operation:

$\text{-x=14-1}$

$\text{-x=13}$

Divide both sides by -1:

$\text{x=-13}$

Note: Since the negative sign is already entered, all you need to enter is 13.

I hope you find my answer helpful.

Good luck!

Have a great day!

$\bf{StargazingWithJoy}$

5 0

3 years ago

Find the surface area of the right cone. Round your answer to the nearest hundredth.

liq [111]

Answer:

Surface Area= 650.65

8 0

3 years ago

The difference of two trinomials is x2 - 10x + 2. If one of the trinomials is 3x? - 11x - 4, then which expression could be the

klio [65]

Answer:

$2x^2-x-6$

or

$4x^2-21x-2$

Step-by-step explanation:

The difference of two trinomials $P(x)$ and $Q(x)$ is $x^2 - 10x + 2.$ This means that

$P(x)-Q(x)=x^2-10x+2$

or

$Q(x)-P(x)=x^2-10x+2$

If one of the trinomials is $P(x)=3x^2-11x - 4,$ then

$(3x^2-11x-4)-Q(x)=x^2-10x+2$

or

$Q(x)-(3x^2-11x-4)=x^2-10x+2$

1. If $(3x^2-11x-4)-Q(x)=x^2-10x+2,$ then

$Q(x)=(3x^2-11x-4)-(x^2-10x+2)\\ \\Q(x)=(3x^2-x^2)+(-11x+10x)+(-4-2)\\ \\Q(x)=2x^2-x-6$

2. If $Q(x)-(3x^2-11x-4)=x^2-10x+2,$ then

$Q(x)=(x^2-10x+2)+(3x^2-11x-4)\\ \\Q(x)=(x^2+3x^2)+(-10x-11x)+(2-4)\\ \\Q(x)=4x^2-21x-2$

4 0

3 years ago

Through (3,5) parallel to y = 5x - 1

qwelly [4]

Answer:

y=5x-10

Step-by-step explanation:

graphed it

7 0

4 years ago

The probability distribution was used along with statistical software to simulate 25 repetitions of the experiment (25 games).

Natali [406]

Answer:

Hello here is the missing data to your question

x P(x)

0 0.167

1 0.3289

2 0.2801

3 0.149

4 0.0382

5 0.0368

The theoretical values are lower than the approximate values and the property illustrated is the mean and standard deviation

A) 1.6729

B) 1.234061

C) 1.84

D) 1.462874

Step-by-step explanation:

A) calculate the theoretical mean

theoretical mean (u) = summation of ; $x_{i}p(x_{i})$

= 0(0.167)+1(0.3289)+2(0.2801)+3(0.149)+4(0.0382)+5(0.0369)

= 1.6729

B) calculate the theoretical standard deviation

theoretical standard deviation = $\sqrt{variance}$ = $\sqrt{[summation of x_{i}^2 p(x_{i} ) ]-u^2}$

= $\sqrt{[0+0.3289+1.1204+1.341+0.6112+0.92]-(2.798594)}$

= 1.234061

C) calculate the approximate mean

the generated data used for calculation is added below

mean (x) = $\frac{summation of (x_{i}) }{n}$ = $\frac{1+2...+2+1}{25}$ = 46/25 = 1.84

D) calculate the approximate standard deviation

std = $\sqrt{variance}$

= $\sqrt{\frac{summation of( x_{i}-x )^2}{n-1} }$

= $\sqrt{2.14}$ = 1.462874

8 0

4 years ago