Answer:
m = 8
Explanation:
A telescope is a device that allows us to see objects that were very far from us, it is built by the combination of two lenses, the one with the lowest focal length near the eye and that is the one or the one with the greatest focal length, the most eye-flounder . The magnification of the telescope is
m = - f₀ /
Where f₀ is the focal length of the lens and f_{e} is the false distance of the eyepiece.
It is this problem that gives us the diopter of each lens, these are related to the focal length in meters
D = 1 / f
Let's find the focal length
f₁ = 1 / D₁
f₁ = 1 / 1.16
f₁ = 0.862 m
f₂ = 1 / 9.37
f₂ = 0.1067 m
Therefore, the lens with f₂ is the eyepiece and the slow one with the
distance focal f₁ is the objective.
Let's calculate
m = - f₂ / f₁
m = - 0.862 / 0.1067
m = 8
Answer:2 amperes
Explanation:
Voltage=120v
Total resistance=15+15+30
Total resistance=60 ohms
Current=voltage ➗ resistance
Current=120 ➗ 60
Current=2 amperes
<span>The correct condition in the nucleus are likely to result in an atom undergoing radioactive decay is that </span><span>d. When the attraction of the strong force is greater than the attraction of the electrostatic force. Radioactivity </span><span>is the process when the unstable nucleus loses energy and emits radiation such as the alpha and beta particles.</span>
Answer:
Explanation:
For answer this we will use the law of the conservation of the angular momentum.
so:
where is the moment of inertia of the merry-go-round, is the initial angular velocity of the merry-go-round, is the moment of inertia of the merry-go-round and the child together and is the final angular velocity.
First, we will find the moment of inertia of the merry-go-round using:
I =
I =
I = 359.375 kg*m^2
Where is the mass and R is the radio of the merry-go-round
Second, we will change the initial angular velocity to rad/s as:
W = 0.520*2 rad/s
W = 3.2672 rad/s
Third, we will find the moment of inertia of both after the collision:
Finally we replace all the data:
Solving for :