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goldenfox [79]
2 years ago
8

A 25. 00 ml sample of acetic acid containing phenolphthalein indicator is titrated with 0. 1067 m naoh. The solution changes col

or after 30. 07 ml naoh has been added. What is the concentration of the acetic acid before titration?.
Physics
1 answer:
Semenov [28]2 years ago
6 0

The concentration of the acetic acid:

The concentration of the acetic acid before titration is 0.128M

Reaction of phenolphthalein with NaOH:

The sodium hydroxide will start interacting with phenolphthalein as soon as enough sodium hydroxide has been added to the acetic acid such that there is no longer any unreacted acetic acid. Pink solution is produced when phenolphthalein and sodium hydroxide combine.

Calculation:

<u>The balanced equation:</u>

CH₃COOH + NaOH ⇒ CH₃COONa + H₂O

<u>Given:</u>

Quantity of NaOH = 0.1067 M

Volume of NaOH = 30.07 ml

                             = 30.07 / 1000

                             = 0.03007 L

For weak acid and strong base titration =  Moles of acetic acid =  moles of NaOH

Moles of NaOH = concentration X volume

0.1067 X 0.03007 = 0.0032

Thus, moles of acetic acid  = 0.0032mole,

By employing the formula,

Concentration = Moles/Volume

                         = 0.0032/0.025

                         = 0.128M

Learn more about the concentration of acetic acid here,

brainly.com/question/15065009

#SPJ4

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