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vagabundo [1.1K]
3 years ago
9

If a curve with a radius of 65 m is properly banked for a car traveling 75 km/h, what must be the coefficient of static friction

for a car not to skid when traveling at 104 km/h?
Physics
1 answer:
STALIN [3.7K]3 years ago
8 0
As a car makes a turn, the force of friction acting upon the turned wheels of the car provides centripetal force required for circular motion. Equation to follow are F = mv²/r  "Force of friction"  Ff= μsN, Normal N=mg Ff=μsmg. Therfore
mv²/r = μsmg  cancel mass "m" The formula to follow will be μs = v²/rg
 
μs = v²/rg  μs = (28.89 m/s²)²/ (65 m)(9.8 m/s²) =  1.31
You might be interested in
A speaker creates uniformly spherical sounds w/ 500 watts of power
sladkih [1.3K]

Answer:

A) I = 0.09947 W , β = 109 db , B) β = 116 db , β = 116 db , c) Δβ = 7 dB,

D)  P = 50.27 W

Explanation:

A) The intensity of a spherical sound wave is

          I = P / A

where A is the area of ​​the sphere where the sound is distributed

          A = 4π R²

       

we substitute

          I = P / 4πR²

let's calculate

          I = 500 / (4π 20²)

          I = 0.09947 W

to express this quantity in decibels we use relate

         β = 10 log (I / I₀)

The detectivity threshold is I₀ = 1 10⁻¹² W / m²

         β = 10 lob (0.09947 / 10⁻¹²)

         β = 10 (10.9976)

         β = 109 db

B) intensity at r = 10m

          I = 500 / (4π 10²)

          I = 0.3979 W / m²

          β = 10 log (0.3979 / 10⁻¹²)

          β = 10 (11.5997)

          β = 116 db

C) the change in intensity in decibles is

          Δβ = β₁ - β₂

          Δβ = 116 - 109

          Δβ = 7 dB

D) let's find the intensity for 100 db

          I = I₀ 10 (β / 10)

          I = 10⁻¹² 10 (100/10)

          I = 10⁻² W / m²

Thus

           P = I A

           P = I 4π R²

           P = 10⁻² 4π 20²

           P = 50.27 W

6 0
3 years ago
A rod 150 cm long and of diameter 2.0 cm is subjected to an axial pull of 20 kn. if the modulus of elasticity of the material of
Scilla [17]
Given:
rod of circular cross section is subjected to uniaxial tension.
Length, L=1500 mm
radius, r = 10 mm
E=2*10^5 N/mm^2
Force, F=20 kN = 20,000 N
[note: newton (unit) in abbreviation is written in upper case, as in  N ]

From given above, area of cross section = π r^2 = 100 π =314 mm^2
(i) Stress,
σ
=force/area
= 20000 N / 314 mm^2
= 6366.2 N/mm^2
= 6370 N/mm^2 (to 3 significant figures)

(ii) Strain
ε
= ratio of extension / original length
= σ / E
= 6366.2 /(2*10^5)
= 0.03183 
= 0.0318 (to three significant figures)

(iii) elongation
= ε * L
= 0.03183*1500 mm
= 47.746 mm
= 47.7 mm  (to three significant figures)

5 0
3 years ago
Which condition is essential for the formation of a standing wave?
frosja888 [35]

Half a wavelength must fit exactly into the length of a vibrating cord

Explanation:

A standing wave is a wave produced by the interference between a wave and its reflection. A standing wave is the wave produced, for instance, in the string of a guitar.

A standing wave is different from other types of waves because it does not propagate in space, but it only vibrate in a fixed region.

A standing wave is characterized by the presence of:

  • Nodes: points where the amplitude of the wave is always zero (destructive interference)
  • Antinodes: points where the amplitude of the wave is maximum (constructive interference)

The two ends of the string do not vibrate: this means that they always correspond to two nodes. If we take the fundamental mode of vibration of the string (so, no other nodes), we see that the length of the string corresponds to the distance between two consecutive nodes: however, this also corresponds to half the wavelength of the wave. Therefore, we can conclude that the correct option is

Half a wavelength must fit exactly into the length of a vibrating cord

Learn more about waves:

brainly.com/question/5354733

brainly.com/question/9077368

#LearnwithBrainly

4 0
3 years ago
A uniform wire of resistance R is cut into three equal lengtsh. one of these is formed into circle and connected between the oth
BARSIC [14]
The resistance between the opposite ends will be 3R/4.
8 0
2 years ago
a uniform beam 6.0 metre long and weighing 4kg rests on support at p and q placed left and right 1.0 metres from each end of the
QveST [7]

Answer:

Explanation:

I need the answer me too

8 0
3 years ago
Read 2 more answers
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