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vagabundo [1.1K]
3 years ago
9

If a curve with a radius of 65 m is properly banked for a car traveling 75 km/h, what must be the coefficient of static friction

for a car not to skid when traveling at 104 km/h?
Physics
1 answer:
STALIN [3.7K]3 years ago
8 0
As a car makes a turn, the force of friction acting upon the turned wheels of the car provides centripetal force required for circular motion. Equation to follow are F = mv²/r  "Force of friction"  Ff= μsN, Normal N=mg Ff=μsmg. Therfore
mv²/r = μsmg  cancel mass "m" The formula to follow will be μs = v²/rg
 
μs = v²/rg  μs = (28.89 m/s²)²/ (65 m)(9.8 m/s²) =  1.31
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Calculate the radiative and collisional energy losses (in keV/micron) for a 1.9 MeV electron in lead and determine the rad./coll
Andrew [12]

Answer:

Explanation:

During an energy transfer, the collision loss for an electron can be determined by using the formula:

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\dfrac{radiational \ energy \ loss}{colisional \ energy \ loss } = \dfrac{ZE}{800}

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b)

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Moreover, the traditional lead with its high density and thickness reduces observation features, in the meantime, the plexiglass is a whole lot higher than the stated.

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4 0
3 years ago
A cyclist has a constant speed of 12 m/s. What is the magnitude of the displacement of the cyclist after 18 seconds?
Katyanochek1 [597]

Answer:

216 m

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An object 82 cm high forms a virtual image 4.1 cm high located 4.6 cm behind a mirror. Find the object distance.
ioda

Answer:

The object distance is 92 cm.  

Explanation:

let v be the image distance and h be the height of the image, let u the be the object distance and H be the height of the object.

then, the magification of the mirror is given by:

m = -v/u and m = h/H

so, -v/u = h/H

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Therefore, the object distance is 92 cm.

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3 years ago
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