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poizon [28]
3 years ago
6

A right circular cylinder has a volume of 1000 cubic inches and a height of 8 inches. What is the radius of the cylinder to the

nearest tenth of a inch?
Mathematics
1 answer:
katovenus [111]3 years ago
7 0
V=πr²h
1000=πr²(8)
r²=39.79
r=6.3
Hope this Helps! :D
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alex41 [277]
160 is the first because 1 inches 20 but it says 2 inches so at 40+40+40+40
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6 0
3 years ago
7) Find the perimeter of triangle ABC. Round all answers to the nearest tenth.[6 points)
dsp73

Answer: 14.6

Step-by-step explanation:

I made a square around the triangle which I then counted the squares, found the Pythagorean theorem, and then added the missing sides together

6 0
2 years ago
A. 3<br> B. 3.1<br> C. 3.8<br> D. 11.6
pishuonlain [190]
Mean = (2+4+6+5+2)/5 = 19/5 = 3.8

answer

<span>C. 3.8</span>
4 0
3 years ago
Help, fast pls. I don't know how to do this and don't have notes for the class.
iogann1982 [59]

Step-by-step explanation:

according to the drawing,

for x = 0 => y = 12

the coordinates of y-intercept : (0, 12)

so, y = f(0) = 12

The correct answer is 12 only

5 0
2 years ago
State whether the triangles could be proven congruent, if possible, by SSS or SAS.
Helen [10]

Answer:

1. SSS

2. SAS

3. SAS

4. SSS

5. SAS

6. SAS

Step-by-step explanation:

1) Side FY ≅ Side CW  Given

Side FP ≅ Side CM     Given

Side YP ≅ Side MW    Given

∴ΔMCW ≅ ΔFPY by the Side-Side-Side (SSS) rule of congruency

2) ∠CBD ≅ ∠BCA given that both are alternate interior angles

Side EB ≅ Side EC and Side DB ≅ Side CA Given

ΔBED ≅ ΔAEC by Side-Angle-Side (SAS) rule of congruency

3. ∠SVU ≅ ∠SVT   Given

Side SV ≅ Side SV  by reflexive property

Side VT ≅ Side VU   Given

∴ ΔVSU ≅ ΔVST by Side-Angle-Side (SAS) rule of congruency

4. Side MN ≅ Side QP  Given

Side MQ ≅ Side NP     Given

Side NQ ≅ Side NQ    by reflexive property

∴ΔQNM ≅ ΔQNP by the Side-Side-Side (SSS) rule of congruency

5. Indirect proof

Side GL ≅ Side HL  Given

Side GJ ≅ Side HK     Given

∠JLG ≅ ∠HLK    vertically opposite angles

By sine rule

GJ/sin(∠JLG) = GL/n(∠GJL)

Similarly

HK/sin(∠HLK) = HL/n(∠HKL)

∴ ∠GJL ≅ ∠HKL

∴ ∠LGJ ≅ ∠LHK third angle of two triangles given the other two angles are congruent

∴ΔQNM ≅ ΔQNP by the Side-Angle-Side (SAS) rule of congruency

6. ∠XZY ≅ ∠XZW   Supplementary ∠s with ∠XZY = 90°

Side XZ ≅ Side XZ  by reflexive property

Side ZW ≅ Side ZY   Given

∴ ΔXYZ ≅ ΔXWZ by Side-Angle-Side (SAS) rule of congruency.

3 0
2 years ago
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