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3 years ago

Which input value produces the same output value for the two functions on the graph?

Mathematics

2 answers:

xeze [42]3 years ago

8 0

X = 4 will give you the same output no matter what graph you are using.

Elena-2011 [213]3 years ago

3 0

Answer:

x=4

Step-by-step explanation:

WE need to find out which input value x value gives the same output value y for the two function f(X) and g(X) on the graph

We look at the point of intersection of both f(x) and g(x)

both graphs intersects at a point (4,3)

It means for the input value x=4 both f(x) and g(x) has same output 3

So input value x=4 produces the same output value for the two functions on the graph.

You might be interested in

A scuba diver descends in the water at a rate of 20 1/2 feet per minute for 2.8 minutes. He immediately changes course when he s

N76 [4]

Answer:

7.4 feet below sea level

Step-by-step explanation:

Assumed the starting point is the sea level 0.

<u>After 2.8 min the diver is at position:</u>

20 1/2 * 2.8 =
20.5 * 2.8 =
57.4 feet below sea level

<u>The position change after next 2 minutes:</u>

25*2 = 50 feet

<u>The position of the diver after 4.8 min:</u>

57.4 - 50 = 7.4 feet below sea level

3 0

3 years ago

Simplify 2 root 3 x 3 root 8

scZoUnD [109]

Answer:

Step-by-step explanation:

Given the expression;

2√3 * 3√√8

= (2*3) * (√3*√8)

= 6 * (√24)

= 6 * √4*6

= 6 * (2√6)

= (6*2)√6

= 12√6

Hence the simplified form of the expression is 12√6

8 0

2 years ago

f(x) = 2<img src="https://tex.z-dn.net/?f=x%5E%7B2%7D" id="TexFormula1" title="x^{2}" alt="x^{2}" align="absmiddle" class="latex

loris [4]

Answer:

No answer is possible

Step-by-step explanation:

First, we can identify what the parabola looks like.

A parabola of form ax²+bx+c opens upward if a > 0 and downward if a < 0. The a is what the x² is multiplied by, and in this case, it is positive 2. Therefore, this parabola opens upward.

Next, the vertex of a parabola is equal to -b/(2a). Here, b (what x is multiplied by) is 1 and a =2, so -b/(2a) = -1/4 = -0.25.

This means that the parabola opens upward, and is going down until it reaches the vertex of x=-0.25 and up after that point. Graphing the function confirms this.

Given these, we can then solve for when the endpoints of the interval are reached and go from there.

The first endpoint in -2 ≤ f(x) ≤ 16 is f(x) = 2. Therefore, we can solve for f(x)=-2 by saying

2x²+x-4 = -2

add 2 to both sides to put everything on one side into a quadratic formula

2x²+x-2 = 0

To factor this, we first can identify, in ax²+bx+c, that a=2, b=1, and c=-2. We must find two values that add up to b=1 and multiply to c*a = -2 * 2 = -4. As (2,-2), (4,-1), and (-1,4) are the only integer values that multiply to -4, this will not work. We must apply the quadratic formula, so

x= (-b ± √(b²-4ac))/(2a)

x = (-1 ± √(1-(-4*2*2)))/(2*2)

= (-1 ± √(1+16))/4

= (-1 ± √17) / 4

when f(x) = -2

Next, we can solve for when f(x) = 16

2x²+x-4 = 16

subtract 16 from both sides to make this a quadratic equation

2x²+x-20 = 0

To factor, we must find two values that multiply to -40 and add up to 1. Nothing seems to work here in terms of whole numbers, so we can apply the quadratic formula, so

x = (-1 ± √(1-(-20*2*4)))/(2*2)

= (-1 ± √(1+160))/4

= (-1 ± √161)/4

Our two values of f(x) = -2 are (-1 ± √17) / 4 and our two values of f(x) = 16 are (-1 ± √161)/4 . Our vertex is at x=-0.25, so all values less than that are going down and all values greater than that are going up. We can notice that

(-1 - √17)/4 ≈ -1.3 and (-1-√161)/4 ≈ -3.4 are less than that value, while (-1+√17)/4 ≈ 0.8 and (-1+√161)/4 ≈ 2.9 are greater than that value. This means that when −2 ≤ f(x) ≤ 16 , we have two ranges -- from -3.4 to -1.3 and from 0.8 to 2.9 . Between -1.3 and 0.8, the function goes down then up, with all values less than f(x)=-2. Below -3.4 and above 2.9, all values are greater than f(x) = 16. One thing we can notice is that both ranges have a difference of approximately 2.1 between its high and low x values. The question asks for a value of a where a ≤ x ≤ a+3. As the difference between the high and low values are only 2.1, it would be impossible to have a range of greater than that.

7 0

2 years ago

What is the answer A B C or D

Vanyuwa [196]

To solve this question, use the Cube surface area formula

Area = 6a^2 in which a = edge.

edge = 8.5

Area = 6(8.5)²

Simplify. Follow PEMDAS

Area = 6(72.25)

Area = 433.5

(C) 433.5 in² is your answer

hope this helps

3 0

3 years ago

Read 2 more answers

Jules reads that 1 pint is equivalent to 0.473 liters. He asks his teacher how many liters there are in a pint. His teacher resp

andrey2020 [161]

One pint is equivalent to 0.473 liters which is approximately 0.47 liters if rounding off nearest to hundredth decimal places and 0.5 liters if rounding off nearest to tenth places.

Further explanation:

Jules reads that one pint is equivalent to 0.473 liters.

$1\,\,{\text{Pint}}=0.473\,\,{\text{liters}}$

But according to his teacher, one pint is about 0.47 liters.

$1\,\,{\text{Pint}}\approx0.47\,\,{\text{liters}}$

His teacher round off a value of one pint in liters nearest to hundredth places.

Also according to his parents, one pint is about 0.5 liters.

$1\,\,{\text{Pint}}\approx0.5\,\,{\text{liters}}$

His parents round off the value of one pint in liters nearest to tenth place.

Therefore, his parents and teachers are both right approximately.

Thus, one pint is equivalent to 0.473 liters which is approximately 0.47 liters if rounding off nearest to hundredth decimal places and 0.5 liters if rounding off nearest to tenth places.

Learn more:

1. Write an algebraic expression for the following word phrase the quotient of r and 12 brainly.com/question/1600376

2. 9 ten thousands ÷ 10 in unit form brainly.com/question/4786449

3. What is the value of the digit 4 in the number 84 230 brainly.com/question/106975

Answer details:

Grade: Middle School

Subject: Mathematics

Chapter: Decimal system

Keywords: Hundredth, pint, decimal places, liters, teacher, approximately, divisor, kg, share, rounding off

3 0

3 years ago