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klasskru [66]
3 years ago
7

If f(x) is a continuous function defined for all real numbers, f(–10) = –2, f(–8) = 5, and f(x) = 0 for one and only one value o

f x, then which of the following could be that x value?
–7
–9
0
2

Mathematics
1 answer:
Vinvika [58]3 years ago
8 0
F(-10)=-2,  f(-8)=5, and f is continuous. All these mean that f(x) is 0 for x in between -10 and -8.

That is, f at -10 is negative, then at -8 is positive. So the graph of f "cuts" the x-axis for an x value in (-10, -8). 

Since there is only one value such that f(x)=0, x can only be -9.


Answer: -9

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baherus [9]

Answer:

1st blank: substitution property of equality

2nd blank: linear pair theorem

3rd blank: substitution property of equality

Step-by-step explanation:

<u>1st blank</u>

∠EIJ ≅ ∠GJI (eq. 1)

∠EIJ ≅ ∠IKL (eq. 2)

∠GJI ≅ ∠JLK (eq. 3)

Substituting eq. 3 into eq. 1:

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<u>2nd blank</u>

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<u>3rd blank</u>

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