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klasskru [66]
3 years ago
7

If f(x) is a continuous function defined for all real numbers, f(–10) = –2, f(–8) = 5, and f(x) = 0 for one and only one value o

f x, then which of the following could be that x value?
–7
–9
0
2

Mathematics
1 answer:
Vinvika [58]3 years ago
8 0
F(-10)=-2,  f(-8)=5, and f is continuous. All these mean that f(x) is 0 for x in between -10 and -8.

That is, f at -10 is negative, then at -8 is positive. So the graph of f "cuts" the x-axis for an x value in (-10, -8). 

Since there is only one value such that f(x)=0, x can only be -9.


Answer: -9

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What is an equation of a line that passes through the points (1,8) and (-1, -2)
Dima020 [189]

Answer:

y = 5x + 3

Step-by-step explanation:

Y = mx + b

find the rise/run

in this case \frac{10}{2} or 5

find b or the y intercept

in this case 3

Hope this helps!

6 0
3 years ago
A circular sign is precisely designed to have an area of 50.24 square inches. What is the sign's circumference?
choli [55]

Step-by-step explanation:

First of all we need to know the formula for the circumference which is: c=2\pi r

We don't have the radius. What we only have is the area; therefore, we must use the area formula and extract the radius from it.

The formula for the area is: A=\pi r^2 Solve for r;

r^2=\frac{A}{\pi}\\ r=\sqrt[]{\frac{A}{\pi} }

r=\sqrt[]{\frac{50.24inch^2}{3.14} }

r=\sqrt[]{16inch^2}\\ r=4inch

Now that we've found the radius, we simply plug it into the circumference formula.

C=2\pi r\\C=2(3.14)(4)\\C=25.12inch

5 0
3 years ago
Find the real or imaginary solutions of each equation by factoring
anyanavicka [17]
Sum of  2 perfect cubes
a³+b³=(a+b)(x²-xy+y²)
so

x³+4³=(x+4)(x²-4x+16)
set each to zero
x+4=0
x=-4

the other one can't be solveed using conventional means
use quadratic formula
for
ax^2+bx+c=0
x=\frac{-b+/- \sqrt{b^2-4ac} }{2a}
for x²-4x+16=0
x=\frac{-(-4)+/- \sqrt{(-4)^2-4(1)(16)} }{2(1)}
x=\frac{4+/- \sqrt{16-64} }{2}
x=\frac{4+/- \sqrt{-48} }{2}
x=\frac{4+/- (\sqrt{-1})(\sqrt{48}) }{2}
x=\frac{4+/- (i)(4\sqrt{3}) }{2}
x=2+/- 2i\sqrt{3}


the roots are
x=-4 and 2+2i√3 and 2-2i√3
8 0
3 years ago
Please help me it needs to be turned in tonight
Katarina [22]

Answer:

Step-by-step explanation:

1) x=14 y=40

2)a=10 b=37

3)u=62 v=59

4)s=9 t=14

5)u=66 v=38

hope this helps

6 0
3 years ago
Select the relations that are functions.
Arlecino [84]

Answer:

Depending on how the input of each function defined,

  • The first choice \left\lbrace(a, 1),\, (6, 1), \, (C, 1)\right\rbrace,
  • The third choice \left\lbrace(1, a),\, (2, a), \, (3, a)\right\rbrace
  • The fourth choice \left\lbrace(a, a),\, (b, b), \, (c, c)\right\rbrace

might be functions.

Step-by-step explanation:

A function between two sets (domain and range) should

  • be defined for all elements in the domain, and
  • map each element from the domain to exactly one element in the range.

The second choice can't be a function since the element a from the domain is mapped to more than one element in the range.

Keep in mind that a function should be defined for all elements in its domain. For the first relation to be a function, its domain needs to be \lbrace a,\, 6, \, C\rbrace. Similarly, the domain for the third and fourth relations should be \lbrace 1,\, 2, \, 3\rbrace and \lbrace a,\, b, \, c\rbrace

8 0
3 years ago
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