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klasskru [66]
2 years ago
7

If f(x) is a continuous function defined for all real numbers, f(–10) = –2, f(–8) = 5, and f(x) = 0 for one and only one value o

f x, then which of the following could be that x value?
–7
–9
0
2

Mathematics
1 answer:
Vinvika [58]2 years ago
8 0
F(-10)=-2,  f(-8)=5, and f is continuous. All these mean that f(x) is 0 for x in between -10 and -8.

That is, f at -10 is negative, then at -8 is positive. So the graph of f "cuts" the x-axis for an x value in (-10, -8). 

Since there is only one value such that f(x)=0, x can only be -9.


Answer: -9

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What is the row echelon form of this matrix?
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The row echelon form of the matrix is presented as follows;

\begin{bmatrix}1 &-2  &-5  \\ 0& 1 &  -7\\ 0&0  &1  \\\end{bmatrix}

<h3>What is the row echelon form of a matrix?</h3>

The row echelon form of a matrix has the rows consisting entirely of zeros at the bottom, and the first entry of a row that is not entirely zero is a one.

The given matrix is presented as follows;

\begin{bmatrix}-3 &6  &15  \\ 2& -6 &  4\\ 1&0  &-1  \\\end{bmatrix}

The conditions of a matrix in the row echelon form are as follows;

  1. There are row having nonzero entries above the zero rows.
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  3. The location of the leading one in a nonzero row is to the left of the leading one in the next lower rows.

Dividing Row 1 by -3 gives:

\begin{bmatrix}1 &-2  &-5  \\ 2& -6 &  4\\ 1&0  &-1  \\\end{bmatrix}

Multiplying Row 1 by 2 and subtracting the result from Row 2 gives;

\begin{bmatrix}1 &-2  &-5  \\ 0& -2 &  14\\ 1&0  &-1  \\\end{bmatrix}

Subtracting Row 1 from Row 3 gives;

\begin{bmatrix}1 &-2  &-5  \\ 0& -2 &  14\\ 0&2  &4  \\\end{bmatrix}

Adding Row 2 to Row 3 gives;

\begin{bmatrix}1 &-2  &-5  \\ 0& -2 &  14\\ 0&0  &18  \\\end{bmatrix}

Dividing Row 2 by -2, and Row 3 by 18 gives;

\begin{bmatrix}1 &-2  &-5  \\ 0& 1 &  -7\\ 0&0  &1  \\\end{bmatrix}

The above matrix is in the row echelon form

Learn more about the row echelon form here:

brainly.com/question/14721322

#SPJ1

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1 year ago
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Hello! We know that we have $400. So 23 ten dollar bills is equal to $230. How? We multiply 23 x 10 and get $230. Then, we have 46 dimes. A dime is worth 10 cents so we multiply 46 x 10 which equals $4.60. And of course we have the 19 cents. Now we add. 400 + 230 + 4.60 + 19 = $653.6.

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