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3 years ago

Help me do question 1. 2. and 3. for 100 points and brainlyest to the first answer. If you need the questions feel free to ask.

Mathematics

2 answers:

ZanzabumX [31]3 years ago

8 0

1.
a. there are 16 nickels so circle 12
b. 12 times 5= 0.60
2.
a. 12 dimes
b. there are 12 dimes so circle 10 (1.00)
3.
a. 10 quarters
b. circle 6 quarters (0.70)

solniwko [45]3 years ago

3 0

If you do 16 /4 then take that answer and multiply it by 3

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$5.10 x 91 gdgdhfhfh

vampirchik [111]

Answer:

464.1

Step-by-step explanation:

5.1 * 91 = 464.1

6 0

1 year ago

Which of the following equations represents a line that passes through the points

Xelga [282]

Answer:

C) I only

Step-by-step explanation:

( -1, -2) and (0,4)

Slope:

m=(y2-y1)/(x2-x1)

m=(4+2)/(0+1)

m=6/1

m=6

Slope-intercept:

y - y1 = m(x - x1)

y + 2 = 6(x + 1)

y + 2 = 6x + 6

y = 6x + 4

y - 16 = 6(x - 2)

y - 16 = 6x - 12

y = 6x + 4

6 0

3 years ago

Find the surface area of a cylinder with a base diameter of 8ft and a height of 6ft. Write your answer in terms of pi, and be su

Ksju [112]

Given that diameter of the base of the cylinder = 8 ft

Given that height of the cylinder = 6 ft

We have to find the surface area of the cylinder in terms of pi.

So we need to use formula of surface area of the cylinder which is

$Area= 2\pi r(r+h)$

where h= height = 6

r= radius = diameter/2 = 8/2 = 4

Now plug these values into above formula

$Area= 2\pi *4(4+3)$

$Area= 2\pi *4(7)$

$Area= 2\pi *28$

$Area= 56\pi$

Hence final answer is

$Area= 56\pi$ square ft

3 0

3 years ago

Read 2 more answers

Which would be the best method to use to solve the following equations? Explain your reasoning.

o-na [289]

A. square root property

$3x^2-192=0\\x^2-66=0\\x^2=66\\x= -\sqrt{66} or \sqrt{66}$

it has one value with x which is x^2 and it cn be easily solved without having to factorise, quadratic formula cant be used as it need ax^2+bx+c=0 format

B. factorising

$x^2-x-6=0\\x^2+2x-3x-6=0\\(x+2)(x-3)=0\\x+2=0 and x-3=0\\x= -2 \\x= 3$

i just felt like this was easier to factorise than the other 2 options left

C. Completing the square

$x^2-6x-7=0\\(x-3)^2=0\\x= -1\\x= 7$

same reason personal preference

D- Quadratic

$x^2-17x-7=0\\x=\frac{-(-17)+\sqrt{(-17)^2-4(1)(-7)} }{2(1)} \\x=\frac{-(-17)-\sqrt{(-17)^2-4(1)(-7)} }{2(1)}\\x=17.4\\x=-0.402$

the 17 kinda threw me off and i didnt wanna get on factorising or doing completing the square so quadratic formal

7 0

2 years ago

The graph of quadratic function f(x) has a minimum at (-2,- 3 and passes through the point (2, 13). The functio

Nadusha1986 [10]

Answer:

Step-by-step explanation:

hello :

the vertex -form of quadratic function f(x) is : f(x) = a(x+b)²+c

the vertex : (- b , c )

means : (-2,-3) so : -b = -2 and c = - 3 so : b =2 and c = -3

f(x) = a(x+2)²-3

calculate : a

the graph passes through the point (2, 13) : f(2)=13

means : a(2+2)²-3 = 13

16a - = 13

16a = 16 so : a = 1

f(x) is represented by the equation f(x) = (x+2)²-3

The graph of f(x) color red and g(x) blue

is the y-intercept when g(x) greater g(x) than f(x) is when x=0 so : y = 6

8 0

3 years ago