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ruslelena [56]
3 years ago
10

Divide and simplify 4/7÷(-11/2)​

Mathematics
1 answer:
lys-0071 [83]3 years ago
4 0

Answer: -\frac{8}{77}

Step-by-step explanation:

\frac{\frac{4}{7} }{-\frac{11}{2} }

Multiply by the reciprocal in order to get rid of the fraction in the denominator.

\frac{\frac{4}{7} }{-\frac{11}{2} }*-\frac{2}{11}

\frac{4}{7}*-\frac{2}{11}

-\frac{8}{77}

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The correct answer will be B
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Answer:

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2 years ago
Children of mothers who smoked during pregnancy scored nine points lower on intelligence tests at ages three and four than child
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Answer:

All of the options apply.

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3 years ago
How many liters each of a 35% acid solution and a 80% acid solution must be used to produce 60 liters of a 65% acid solution? (R
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Solving a system of equations we will see that we need to use <u>40 liters of the 80% acid solution</u>, and the other <u>20 liters are of the 35% acid solution</u>.

<h3>How many liters of each solution do we need to use?</h3>

First, we need to define the variables:

  • x = liters of the 35% acid used.
  • y = liters of the 80% acid used.

We know that we want to produce 60 liters of 65% acid, then we have the system of equations:

x + y = 60

x*0.35 + y*0.80 = 60*0.65

(in the second equation we wrote the percentages in decimal form).

To solve this we need to isolate one of the variables in one equation and then replace it in other one, isolating x we get:

x = 60 - y

Replacing that in the other equation:

(60 - y)*0.35 + y*0.80 = 60*0.65

y*(0.80 - 0.35) = 60*(0.65 - 0.35)

y*0.45 = 60*0.30

y = 60*0.30/0.45 = 40

So we need to use <u>40 liters of the 80% acid solution</u>, and the other <u>20 liters are of the 35% acid solution</u>.

If you want to learn more about systems of equations:

brainly.com/question/13729904

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