There are C(5,2) = 10 ways to choose 2 contraband shipments from the 5. There are C(11, 1) = 11 ways to choose a non-contraband shipment from the 11 that are not contraband. Hence there are 10*11 = 110 ways to choose 3 shipments that have 2 contraband shipments among them.
There are C(16,3) = 560 ways to choose 3 shipments from 16. The probability that 2 of those 3 will contain contraband is
110/560 = 11/56 ≈ 19.6%
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C(n,k) = n!/(k!(n-k)!)
Answer:
<h2>5 - y</h2>
Step-by-step explanation:
Given the statement "subtract y from 5", we are to express the statement mathematically. Expressing mathematically is as shown;
5 - y
Since we are removing the value of a variable y from 5, <u>the variable we are subtracting will come last in the expression</u>. For example say, we want to subtract 5 from 10, since we are taking out 5 from 10, the value of 5 will come last in the expression i.e 10 - 5 not 5 - 10.
According to the statement in question, we can see that we are to subtract y from 5, therefore <u>y will come last in our expression</u> and will be expressed as 5 - y
Answer:
$97.50
Step-by-step explanation: