Using derivatives, it is found that the correct option is:
A. Object C has an acceleration that is greater than the acceleration for D.
The acceleration is the <u>derivative of the velocity</u>, given by change in velocity divided by change in time, that is:
In this problem:
- The change in time for objects C and T is the same.
- The <u>change in velocity for object C is greater</u>, thus, it has a greater acceleration, and the correct option is:
A. Object C has an acceleration that is greater than the acceleration for D.
A similar problem is given at brainly.com/question/14516604
Answer:
Maria and Antonio
Step-by-step explanation:
sorry if it's wrong
Hope you are able to understand the solution. :-D
Answer:
is the answer.
Step-by-step explanation:
Well the first thing we would do is simplify all the exponents first inside the parenthesis. So 2^-3 is equal to 1/8. To solve negative exponents you would just divide the number instead of multiply, so 2 divided by 2 divided by 2 is equal to ⅛ or .125
Next would be to do the 2^-9. This would equal 1/512
Now would be to simplify 5^0. Anything to the power of 0 is always one. So now we simplify all the products meaning 7*5*2 and 7*3.
Now we would simplify both fractions.
The picture are pretty much self explanatory. If you have any questions feel free to ask in the comments - Mark
Also when you have the chance please mark me brainliest.
The oldest son will get $370, the middle will get $220 and the youngest will get $185.
Step-by-step explanation:
Given,
Total amount to be split = $775
Let,
Oldest son's share = x
Middle son's share = y
Youngest son's share = z
According to given statement;
x+y+z=775 Eqn 1
the oldest gets twice as much as the youngest
x = 2z Eqn 2
the middle son gets $35 more than the youngest
y = z+35 Eqn 3
Putting value of x and y from Eqn 2 and 3 in Eqn 1
Dividing both sides by 4
Putting z=185 in Eqn 2
Putting z=185 in Eqn 3
The oldest son will get $370, the middle will get $220 and the youngest will get $185.
Keywords: linear equation, substitution method
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