First we need to find the number of moles of hydrogen gas formed
Zn + 2HCl ---> ZnCl₂ + H₂
stoichiometry of Zn to H₂ is 1:1
the number of Zn moles reacted - 2.4 g / 65.4 g/mol = 0.0367 mol
assuming Zn to be the limiting reactant
number of Zn moles reacted = number of H₂ moles formed
therefore number of H₂ moles formed = 0.0367 mol
we can use ideal gas law equation to find the pressure
PV = nRT
P - pressure
V - Volume - 450 x 10⁻⁶ m³
n - number of moles - 0.0367 mol
R - universal gas constant - 8.314 Jmol⁻¹K⁻¹
T - temperature - 32 °C + 273 = 305 K
substituting these values in the equation
P x 450 x 10⁻⁶ m³ = 0.0367 mol x 8.314 Jmol⁻¹K⁻¹ x 305 K
P = 206.8 kPa
pressure is 206.8 kPa
CO(g) +2H2--->CH3OH
2.50g H2*1mol/2g=1.25 mol H2
30.0L CO*1mol/22.4L=1.34 mol CO,
according to reaction 1 mol CO needs 2 mol H2,so 1.34 mol CO need 2.68 mol H2, so 1) limiting teactant is H2 (H)
2)1.25 mol CH3OH will be produced, 1.25 mol*32g/mol=40.0 g CH3OH
3) 1.25 mol H2 needs 0.625 g CO
1.34-0.625=0.715 g CO leftover
Answer:
103.2 g of AgCl can be made in the reaction
Explanation:
We state the reaction to analyse the problem:
AlCl₃ + 3AgNO₃ → 3AgCl + Al(NO₃)₃
We convert the mass of chloride to moles:
32 g . 1mol/ 133.34g = 0.240 moles
Ratio is 1:3. See the stoichiometry
1 mol of aluminum chloride can produce 3 moles of AgCl
Then, 0.240 will produce (0.240 . 3)/1= 0.720 moles.
We convert the moles to mass: 0.720 mol . 143.32g/1mol = 103.2 g
Answer:
6 moles of oxygen, or 3O2.
Explanation:
I would build a proportion for this:
