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kow [346]
3 years ago
13

According to which virtue do you need to secure information by limiting computer access to authorized personnel only ?

Computers and Technology
2 answers:
nadya68 [22]3 years ago
8 0

Confidentiality is a virtue which we need to secure information by limiting computer access to authorized personnel only. People trust us to keep their private matters private. Keeping that confidence is an important aspect of trust.  

vagabundo [1.1K]3 years ago
7 0

Answer:

The correct answer to the following question will be "Confidentiality".

Explanation:

Confidentiality seems to be a protection that we use to protect knowledge by restricting only permitted staff access to the device. Personnel details are private, so documents found in an individual employee folder, including SSN, compensation, health history, administrative proceedings so the justification for dismissal, can not be shared with anyone.

  • Citizens expect us to keep confidential about certain private affairs.
  • Holding the faith seems to be an essential part of confidence or belief.

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You are starting a small web hosting business and
Studentka2010 [4]

Answer:

otp

Explanation:

don't know bro ask to your teacher

7 0
3 years ago
Write a function called count_occurrences that takes two strings. The second string should only be one character long. The funct
iVinArrow [24]

Answer:

Here is the Python function:

def count_occurrences (string1 , string2):  # method that takes two strings as parameter and returns how many times second string occurs in first

   count = 0  #counts number of occurrence of string2 in string1

   for word in string1:  #iterates through each word of the string1

       for character in word:  #iterates through each character of each word in string1

           if character == string2:  # checks if the character in string1 is equal to the character of string2

               count = count + 1  #adds 1 to the count of string2 in string1

   return count  #returns number of times the string2 occurs in string1

#in order to check the working of the function add the following lines to the code:    

first_str = input("Enter the first string: ")  #prompts user to enter first string

second_str = input("Enter the second string (one character long): ") #prompts user to enter second string which should be one character long

occurrence = count_occurrences(first_str,second_str)  #calls count_occurrences method by passing both strings to it

print(second_str,"occurs",occurrence,"times in",first_str) #prints how many times the second_str occurs in the first_str on output screen

Explanation:

The program is well explained in the comments added to each statement of the above code. I will explain the program with an example:

Suppose

string1 = "hello world"

string2 = 'l'

So the method count_occurrences() should return how many times l occurs in hello world.

count is used to count the number of occurrences of l in hello world. It is initialized to 0.

The first loop iterates through each word of string1. The first word of string1 is "hello"

The second loop iterates through each character/letter of each word. So the first letter of "hello" word is 'h'.

The if condition if character == string2: checks if the character is equal to string2 i.e. l.

character = "h"

string2 = "l"

The are not equal so the program moves to the next character of word hello which is e. The if condition again evaluates to false because e is not equal to l. So the program moves to the next character of word hello which is l.

This time the if condition evaluates to true because

character = "l"

string2 = "l"

character == string2

l == l

So the if part is executed which has the following statement:

count = count + 1

So the count is added to 1. count was 0 previously. Now

count = 1

Next the program moves to the next character of word hello which is l. This time the if condition evaluates to true because the character l matches with string2. So count is again incremented to 1. count = 2.

Next the program moves to the next character of word hello which is o. The if condition evaluates to false as o does not match with string2 i.e. l. So the count remains 2.

Next the first loop moves to the next word of the string1 = "world". The inner (second) for loop iterates through each character of "world" from "w" to "d" and checks if any character is equal to string2. Only one character is equal to string2 in "world". So count is incremented to 1. Hence count = 3

After the loop ends the statement return count returns the number of times string2 occurs in the string1. So the output is:

l occurs 3 times in hello world  

8 0
3 years ago
A broker statement is an example of an ___ record
VARVARA [1.3K]

Answer: investment

Explanation:

3 0
3 years ago
Read 2 more answers
5.17 (Calculating Sales) An online retailer sells five products whose retail prices are as follows: Product 1, $2.98; product 2,
Dima020 [189]

Answer:

import java.util.Scanner;

public class Main

{

public static void main(String[] args) {

   

    //Initialize the prices as constants

    final double PRODUCT_1_PRICE = 2.98;

    final double PRODUCT_2_PRICE = 4.50;

    final double PRODUCT_3_PRICE = 9.98;

    final double PRODUCT_4_PRICE = 4.49;

    final double PRODUCT_5_PRICE = 6.87;

   

    //Declare the other variables

    int productNumber, quantitySold;

    double total = 0.0;

   

    //Create a Scanner object to get input

    Scanner input = new Scanner(System.in);

   

    //Create a while loop

    while(true){

        //Ask the user to enter the productNumber

     System.out.print("Enter the product number or 999 to quit: ");

     productNumber = input.nextInt();

     

     // Stop the loop, if productNumber is 999(sentinel value, you may choose any value you want)

     if(productNumber == 999)

         break;

     

     //Ask the user to enter the quantitySold

     System.out.print("Enter the quantity sold: ");

     quantitySold = input.nextInt();

     

     //Create a switch statement that works depending on the productNumber entered.

     //For example, if the productNumber is 1, it multiplies the quantitySold by PRODUCT_1_PRICE

     //   and adds the result to the total. If productNumber is 2, it does the same for product 2 ...

     switch(productNumber){

         case 1:

             total += quantitySold * PRODUCT_1_PRICE;

             break;

         case 2:

             total += quantitySold * PRODUCT_2_PRICE;

             break;

         case 3:

             total += quantitySold * PRODUCT_3_PRICE;

             break;

         case 4:

             total += quantitySold * PRODUCT_4_PRICE;

             break;

         case 5:

             total += quantitySold * PRODUCT_5_PRICE;

             break;

     }

    }

 

 //Print the total (when the loop is done)

 System.out.println("The total is $" + total);

}

}

Explanation:

*The code is in Java.

You may see the explanation as comments in the code.

4 0
3 years ago
A technique for identifying and tracking assets using technologies such as RFID and smart cards is known as electronic tagging.
Mademuasel [1]

Answer: True

Explanation: Electronic tagging is defined as the activity in which the monitoring of the things and people are done through the electronic markers or device .This process is usually done by attaching a tag sized component on the ankle of the human to monitor them.

The tracking of the good and human is done by production of the time alerts through the tag .Thus the statement given in the question is true.

4 0
3 years ago
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