These types of equations are called simultaneous equations and the method we can use to solve these type of equations is either Substitution, Elimination and Graphing.

We use substitution here because it is easier.

Equation 1

$7x-2y=16$

Equation 2

$11x+6y=32.3$

Lets take equation 1

$7x-2y=16\\7x=16+2y\\x=\frac{16+2y}{7}$

This is our equation 3 , now put it inside equation 2.

$11x+6y=32.3\\11(\frac{16+2y}{7} )+6y=32.3\\\frac{176+22y}{7} +6y=32.3\\\frac{176+22y+42y}{7}=32.3\\176+22y+42y=226.1 \\\\42y+22y=226.1-176\\64y=50.1\\y=\frac{50.1}{64} \\y=0.783\\$

We found the value of y , now to find the value of x insert the value of y in equation 3

$x=\frac{16+2y}{7}\\x=\frac{16+2(0.783)}{7} \\x=\frac{16+1.566}{7}\\x=\frac{17.566}{7}\\x=2.509$

Solved ! See the attached image on both the straight line graphs i have attached for better understanding. Where both the lines intersect each other is our value of (x , y) respectively.

6 0

3 years ago

Multiply y^2-16/2y . 5y/y-4

alisha [4.7K]

So, first we multiply the fraction by using the formula a/b times c/d= a times c/b times d
=(y^2-16) times 5y/2y(y-4)
Now, we cancel the common factor y
=(y^2-16) times 5/2(y-4)
Now, we factor 5(y^2-16)
We factor (y^2-16) first
y^2-16
Rewrite 16 as 4^2
y^2-4^2
Now, apply the formula x^2-y^2=(x+y)(x-y)
=y^2-4^2=(y+4)(y-4)
=5(y+4)(y-4)
=5(y+4)(y-4)/2(y-4)
Cancel the common factor y-4
=5(y+4)/2
Answer: 5(y+4)/2

5 0

3 years ago

Find the force it would take to accelerate an 800-kg car at a rate of 5 m/s^2.

Mars2501 [29]

800/5 which is 160!!!!!!!!

5 0

3 years ago

PLSSS HELP IF YOU TURLY KNOW THISS

dmitriy555 [2]

Answer:

Step-by-step explanation:

to change a mixed number into an improper fraction