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Pavlova-9 [17]
3 years ago
10

Can you help me with my homework i dont get division ;(

Mathematics
1 answer:
myrzilka [38]3 years ago
3 0
D) 4.6 - THOUGHT
E) 16.75 (rounded to 16.8) - THAT
G) 9.73 - PERCUSSION
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In tide pool there are 26 spotted fish and 12 plain fish what is the ratio of spotted fish to plain fish
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Answer: 26/12

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Use the given information to find the p​-value. ​Also, use a 0.05 significance level and state the conclusion about the null hyp
Hatshy [7]

Answer:

We can assume that the statistic is z_{calc}=0.78

p_v = 2* P(z>0.78) = 0.435

So the p value obtained was a very high value and using the significance level given \alpha=0.05 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the true proportion of interest is not different from 3/5

Step-by-step explanation:

Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the true proportion is equal to 3/5 or not.:  

Null hypothesis:p=3/5  

Alternative hypothesis:p \neq 3/5  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

Calculate the statistic  

We can assume that the statistic is z_{calc}=0.78

Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.05. The next step would be calculate the p value for this test.  

Since is a bilateral test the p value would be:

p_v = 2* P(z>0.78) = 0.435

So the p value obtained was a very high value and using the significance level given \alpha=0.05 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the true proportion of interest is not different from 3/5

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3 years ago
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sergey [27]

Answer:

c.

Step-by-step explanation:

AB=√(5²+8²)=√(25+64)=√89

cos A=8/\sqrt{89} =(8\sqrt{89} )/89

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14 x 12 x 48 = 8,064 baskets of pears
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