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zimovet [89]
3 years ago
10

Please can you work this out ( your supposed to use a calculator but mine is broken)

Mathematics
1 answer:
rosijanka [135]3 years ago
6 0

Answer:

(5.4 \times  {10}^{5} ) + (5.3 \times  {10}^{6}) \\ (0.54 \times  {10}^{6}  ) + (5.3 \times  {10}^{6} ) \\  =   5.84\times {10}^{6}  \\  = 5840000

I hope I helped you^_^

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A forestry company hopes to generate credits from the carbon sequestered in its plantations.The equation describing the forest w
Dmitry [639]

Answer:

Explanation:

Given:

The equation describing the forest wood biomass per hectare as a function of plantation age t is:

y(t) = 5 + 0.005t^2 + 0.024t^3 − 0.0045t^4

The equation that describes the annual growth in wood biomass is:

y ′ (t) = 0.01t + 0.072t^2 - 0.018t^3

To find:

a) The year the annual growth achieved its highest possible value

b) when does y ′ (t) achieve its highest value?

a)

To determine the year the highest possible value was achieved, we will set the derivative y'(t) to zero. The values of t will be substituted into the second derivative to get the highest value

\begin{gathered} 0\text{ = 0.01t + 0.072t}^2\text{ - 0.018t}^3 \\ using\text{ a graphing tool,} \\ t\text{  = -0.1343} \\ \text{t = 0} \\ t\text{ = 4.1343} \\  \\ Since\text{ we can't have time as a negative value, t = 0 or t = 4.1343} \end{gathered}\begin{gathered} To\text{ ascertain which is the maximum, we take a second derivative} \\ y^{\prime}\text{'\lparen t\rparen = 0.01 + 0.144t - 0.054t}^2 \\  \\ substitute\text{ t = 0 and t = 4.13 respectively} \\ when\text{ t = 0 } \\ y^{\prime}\text{'\lparen t\rparen= 0.01 + 0.144\lparen0\rparen - 0.054\lparen0\rparen}^2 \\ y^{\prime}\text{'\lparen t\rparen= 0.01 + 0 - 0} \\ y^{\prime}\text{'\lparen t\rparen= 0.01 > 0} \\  \\ y^{\prime}\text{'\lparen t\rparen= 0.01 + 0.144\lparen4.13\rparen - 0.054\lparen4.13\rparen}^2 \\ y^{\prime}\text{'\lparen t\rparen= -0.316 < 0} \\  \\ if\text{ }y^{\prime}\text{'\lparen t\rparen > 0 , then it is minimum, } \\ if\text{ }y^{\prime}\text{'\lparen t\rparen < 0, then it is maximum} \end{gathered}

SInce t = 4.13, gives y ′' (t) = -0.316 (< 0). This makes it the maximum value of t

The year the annual growth achieved its highest possible value to the nearest whole number will be

year 4

b) y ′ (t) will achieve its highest value, when we substitute the value of t that gives into the initial function.

Initial function: y(t) = 5 + 0.005t^2 + 0.024t^3 − 0.0045t^4

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6 0
1 year ago
WILL GIVE BRILLIANTIEST!
tensa zangetsu [6.8K]

Answer c

Step-by-step explanation:

4 0
3 years ago
What are two numbers that when multiplied equal -2, and also when added equals 1
lara [203]
Two numbers that multiply to -2 could be

-1 and 2

Or

-2 and 1.

Since -1+2=1, -1 and 2 are the numbers you are looking for.

Hope this helps!
4 0
3 years ago
Read 2 more answers
F(x) = 2/x, g(x) = |x| -1 <br><br><br> What is the domain of (fog) (x)?<br><br> will mark brainliest
brilliants [131]

Answer:

x≠-1,1

Step-by-step explanation:

f(g(x)) is a composition where g(x) is is substituted for x in f(x).

Recall, f(x) is 2/x. So we write 2/|x|-1. This places x in the denominator and 0 cannot be in the denominator x. Any value of x that makes the denominator 0 will not be in the domain.

|x|-1=0

|x|=1

x=1,-1

3 0
3 years ago
What is the area of a circle with diameter 8cm? Round your answer to the nearest tenth. use pi= 3.14
hodyreva [135]

Answer:

50.2 square cm

Step-by-step explanation:

Diameter = 8 cm

Radius = 8/2 = 4 cm

area \: of \: circle = \pi {r}^{2}  \\  = 3.14 \times  {4}^{2}  \\  = 3.14 \times 16 \\  = 50.24 \:  {cm}^{2}  \\  = 50.2 \:  {cm}^{2}

7 0
3 years ago
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