Answer:
Depends
Step-by-step explanation:
,
Answer:
x^2+y^2 = 3^2
Step-by-step explanation:
We need to eliminate the parameter t
Given:
x = 3 cos t
y = 3 sin t
Squaring the above both equations
(x)^2=(3 cos t)^2
(y)^2 =(3 sin t)^2
x^2 = 3^2 cos^2t
y^2=3^2 sin^2t
Now adding both equations
x^2+y^2=3^2 cos^2t+3^2 sin^2t
Taking 3^2 common
x^2+y^2=3^2 (cos^2t+sin^2t)
We know that cos^2t+sin^2t = 1
so, putting the value
x^2+y^2=3^2(1)
x^2+y^2 = 3^2
Hence the parameter t is eliminated.
Answer:
|x| + 6
Step-by-step explanation:
For F= (x) substitute x with g(x) = |x| + 6
Answer: -3
All work is shown in the attached sheet! :)
_121_ R7 or 121 7/13
13)1580
13
28
26
20
13
7