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Stels [109]
3 years ago
7

Two cards are selected at random without replacement from a well-shuffled deck of 52 playing cards. Find the probability of the

given event. (Round your answer to four decimal places.)
Two cards of the same suit are drawn.
Mathematics
2 answers:
Ne4ueva [31]3 years ago
6 0
The probability of drawing, say, two clubs is:
\frac{1}{4}\times\frac{12}{51}=0.058824
The probabilities of drawing two hearts, two spades or two diamonds is also 0.058824 for each event. The four events are mutually exclusive, therefore the probability of drawing two cards of the same suit is:
0.058824\times 4=0.2353
solmaris [256]3 years ago
4 0

There are 52 cards in a deck of cards. In the first try, the probability of getting any card is 1/52. In the second try, there are already 51 cards because there is no replacement, hence the probability on the second try is 1/51. Hence the probavility of the two events is 1/52*1/51 equal to  1/2652.
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y = 8

Step-by-step explanation:

Equation of the line that passes through (-2, 8) with a slope of 0, can be written in point-slope form, y - y_1 = m(x - x_1) and also in slope-intercept form, y = mx + b.

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