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4 years ago

Choose the function that shows the correct transformation of the quadratic function shifted two units to the right one unit up.

1 answer:

7 0

The function that shows the correct transformation of the quadratic function shifted two units to the right one unit up is 4

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Which measure is always the 50th percentile?

melomori [17]

Answer

The median

Explanation

50th percentile is one of the central tendency. It is used in statisticts to find the median of a set of data.

Used in data analysis such as examinations, population. products and many others.

5 0

4 years ago

Which ordered pair is a solution of the equation?<br> y=3x+5

madam [21]

I hope you’re having a good day so far

6 0

3 years ago

Given that abcd ~Jklm. Find the value of x, y, and z

Minchanka [31]

Answer:

x = 7.2

y = 10

z = 6

Step-by-step explanation:

Since ABCD ~ JKLM, therefore, the ratio of their corresponding sides would be equal. Thus:

JK/AB = KL/BC = LM/CD = JM/AD

Substitute

12/x = y/6 = 15/9 = 10/z

✔️Find x:

12/x = 15/9

12/x = 5/3

Cross multiply

x*5 = 3*12

5x = 36

x = 36/5

x = 7.2

✔️Find y:

y/6 = 15/9

y/6 = 5/3

Cross multiply

y*3 = 5*6

3y = 30

y = 30/3

y = 10

✔️Find z:

15/9 = 10/z

5/3 = 10/z

Cross multiply

5*z = 10*3

5z = 30

z = 30/5

z = 6

4 0

3 years ago

A sample of 900 computer chips revealed that 61% of the chips fail in the first 1000 hours of their use. The company's promotion

Vlad [161]

Answer:

The p-value of the test is 0.0301 > 0.02, which means that there is not sufficient evidence at the 0.02 level to support the company's claim.

Step-by-step explanation:

The company's promotional literature claimed that under 64% fail in the first 1000 hours of their use.

At the null hypothesis, we test if the proportion is of at least 64%, that is:

$H_0: p \geq 0.64$

At the alternative hypothesis, we test if the proportion is of less than 64%, that is:

$H_1: p < 0.64$

The test statistic is:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

In which X is the sample mean, $\mu$ is the value tested at the null hypothesis, $\sigma$ is the standard deviation and n is the size of the sample.

64% is tested at the null hypothesis:

This means that $\mu = 0.64, \sigma = \sqrt{0.64*0.36}$

A sample of 900 computer chips revealed that 61% of the chips fail in the first 1000 hours of their use.

This means that $n = 900, X = 0.61$

Value of the test statistic:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

$z = \frac{0.61 - 0.64}{\frac{\sqrt{0.64*0.36}}{\sqrt{900}}}$

$z = -1.88$

P-value of the test and decision:

The p-value of the test is the probability of finding a sample proportion below 0.61, which is the p-value of z = -1.88.

Looking at the z-table, z = -1.88 has a p-value of 0.0301.

The p-value of the test is 0.0301 > 0.02, which means that there is not sufficient evidence at the 0.02 level to support the company's claim.

8 0

3 years ago

Division the following simply your answer

8_murik_8 [283]

Answer:

1) 12 - 8/3 = ((12*3)-(8))/3 = 28/3

2) 10/ (4/7) = (10/1)*(7/4) = 70/4

3) 12/5 + 4/6 = ((5*4)+(12*6))/(5*6) = 46/15

6 0

3 years ago