Answer:
A. x = 2, y = 7
Step-by-step explanation:
I graphed the equations on the graph below to find the solution to the system of linear equations.
Still need help??!? if so I have and idea probably -∞yuf4
Answer:
in this method a variable is expressed in terms of another variable from one equation and it is substituted in remaining equation.
Step-by-step explanation:
solve:x+2y=9 and 3x-y=13.
x+ 2y=9…be the first equation
3x-y=13…be the second equation
from first equation
x=9-2y…be the third equation substituting value of x from third equation in second equation, we get
3(9-2y)-y=13
or, 27-6y-y=13
or, y=2
now,
substituting value of y in third equation, we get,
x=9-2×2
=9-4
=5
the required value of x and y are 5&2
The answer is A) Dilation, because a dilation makes an object bigger or smaller. hope this helped :D
Answer:
see explanation
Step-by-step explanation:
The inverse of a matrix A =
is
=
![\left[\begin{array}{ccc}d&-b\\-c&a\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Dd%26-b%5C%5C-c%26a%5C%5C%5Cend%7Barray%7D%5Cright%5D)
If ad - bc = 0 then the matrix has no inverse
A = ![\left[\begin{array}{ccc}11&-5\\3&-1\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D11%26-5%5C%5C3%26-1%5C%5C%5Cend%7Barray%7D%5Cright%5D)
ad - bc = (11 × - 1) - (- 5 × 3) = - 11 - (- 15) = - 11 + 15 = 4 , then
=
= ![\left[\begin{array}{ccc}-0.25&0.75\\-1.25&2.75\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-0.25%260.75%5C%5C-1.25%262.75%5C%5C%5Cend%7Barray%7D%5Cright%5D)