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Eddi Din [679]
2 years ago
9

PLSSS HELP THIS IS HARD ANYONE

Mathematics
1 answer:
enyata [817]2 years ago
7 0

Answer:

Step-by-step explanation:

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Solve the system of linear equations below.
Ugo [173]

Answer:

A. x = 2, y = 7

Step-by-step explanation:

I graphed the equations on the graph below to find the solution to the system of linear equations.

3 0
3 years ago
Write the inequality that represents the solution set for −6z17<−23
Rashid [163]
Still need help??!? if so I have and idea probably -∞yuf4
8 0
3 years ago
Could someone pls send me an example of using the substitution method in algebra?
Elden [556K]

Answer:

in this method a variable is expressed in terms of another variable from one equation and it is substituted in remaining equation.

Step-by-step explanation:

solve:x+2y=9 and 3x-y=13.

x+ 2y=9…be the first equation

3x-y=13…be the second equation

from first equation

x=9-2y…be the third equation substituting value of x from third equation in second equation, we get

3(9-2y)-y=13

or, 27-6y-y=13

or, y=2

now,

substituting value of y in third equation, we get,

x=9-2×2

=9-4

=5

the required value of x and y are 5&2

8 0
3 years ago
20 points
Anna11 [10]
The answer is A) Dilation, because a dilation makes an object bigger or smaller. hope this helped :D 
7 0
3 years ago
PLEASE HELP! find the inverse matrix​
Sauron [17]

Answer:

see explanation

Step-by-step explanation:

The inverse of a matrix A = \left[\begin{array}{ccc}a&b\\c&d\\\end{array}\right] is

A^{-1} = \frac{1}{ad-bc} \left[\begin{array}{ccc}d&-b\\-c&a\\\end{array}\right]

If ad - bc = 0 then the matrix has no inverse

A = \left[\begin{array}{ccc}11&-5\\3&-1\\\end{array}\right]

ad - bc = (11 × - 1) - (- 5 × 3) = - 11 - (- 15) = - 11 + 15 = 4 , then

A^{-1} = \frac{1}{4} \left[\begin{array}{ccc}-1&3\\-5&11\\\end{array}\right] = \left[\begin{array}{ccc}-0.25&0.75\\-1.25&2.75\\\end{array}\right]

3 0
3 years ago
Read 2 more answers
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