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Nina [5.8K]
3 years ago
7

A sample contains 10 g of a radioactive isotope. How much radioactive isotope will remain in the sample after 2 half-lives?

Physics
2 answers:
xxMikexx [17]3 years ago
5 0
The answer c - Half life how to figure, you first divide it by half then divide than number by half
k0ka [10]3 years ago
3 0

Answer:

c) 2.5 g

Explanation:

half-life is the time it takes the radioactive isotope to decay to half of the intial sample.

so if the isotope decays to 2 half-lives, it will decay half the intial sample twice.

in the first half-life, the sample will decay from 10 g to 5 g. during the second half-life, the isotope will decay from 5 g to 2.5 g.

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the answer is static friction


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3 years ago
Money is not a medium of exchange for acquiring goods and services.<br> a. True<br> b. False
bonufazy [111]

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Answer:

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7 0
3 years ago
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A 50-g cube of ice, initially at 0.0°C, is dropped into 200 g of water in an 80-g aluminum container, both initially at 30°C.
MakcuM [25]

Answer:

b. 9.5°C

Explanation:

m_i = Mass of ice = 50 g

T_i = Initial temperature of water and Aluminum = 30°C

L_f = Latent heat of fusion = 3.33\times 10^5\ J/kg^{\circ}C

m_w = Mass of water = 200 g

c_w = Specific heat of water = 4186 J/kg⋅°C

m_{Al} = Mass of Aluminum = 80 g

c_{Al} = Specific heat of Aluminum = 900 J/kg⋅°C

The equation of the system's heat exchange is given by

m_i(L_f+c_wT)+m_wc_w(T-T_i)+m_{Al}c_{Al}=0\\\Rightarrow 0.05\times (3.33\times 10^5+4186\times T)+0.2\times 4186(T-30)+0.08\times 900(T-30)=0\\\Rightarrow 1118.5T-10626=0\\\Rightarrow T=\dfrac{10626}{1118.5}\\\Rightarrow T=9.50022\ ^{\circ}C

The final equilibrium temperature is 9.50022°C

4 0
3 years ago
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Tamiku [17]

Answer:

I Will say the Answer is A

Explanation:

5 0
2 years ago
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