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enyata [817]
2 years ago
10

The Sex Equity in Education Act requires educational institutions to distribute a sexual harassment policy to:

Physics
1 answer:
Pie2 years ago
4 0
A.) faculty and parents
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Average speed is the total distance divided by the
seraphim [82]
<h2>Answer:</h2>

Time

<h2>Explanation:</h2>

The average speed of an object that is moving is defined as the distance traveled  divided by the time of travel. You can measure the distance with a ruler and the time with a stopwatch. This can be expressed as the following formula:

v=\frac{\Delta x}{\Delta t}

For instance, if an object travels a distance \Delta x=100m in 4 seconds, the the average speed is:

v=\frac{100m}{4s} \\ \\ \therefore \boxed{v=25m/s}

8 0
3 years ago
A satellite with mass 6000 kg is orbiting the planet at 2500 km above the planet's
9966 [12]

By the law of universal gravitation, the gravitational force <em>F</em> between the satellite (mass <em>m</em>) and planet (mass <em>M</em>) is

<em>F</em> = <em>G</em> <em>M</em> <em>m</em> / <em>R </em>²

where

<em>• G</em> = 6.67 × 10⁻¹¹ m³/(kg•s²) is the universal gravitation constant

• <em>R</em> = 2500 km + 5000 km = 7500 km is the distance between the satellite and the center of the planet

Solve for <em>M</em> :

<em>M</em> = <em>F R</em> ² / (<em>G</em> <em>m</em>)

<em>M</em> = ((3 × 10⁴ N) (75 × 10⁵ m)²) / (<em>G</em> (6 × 10³ kg))

<em>M</em> ≈ 2.8 × 10¹⁴ kg

6 0
2 years ago
B) Smartphone, iPad, and tablet are also a kind of computer.
valentinak56 [21]

Answer:

Yes

Explanation:

7 0
3 years ago
How tall would a tower need to be if the period of a pendulum were 30. seconds
Virty [35]
We use the following expression

T = 2*pi *sqrt(l/g)

Where T is the period of the pendulum

l is the length of the pendulum

and g the acceleration of gravity

We solve for l

l = [T/2*pi]² *g = [30s/2*pi]²* 9.8 [m/s²] = 223.413 m

The tower would need to be at least 223.413 m high
4 0
3 years ago
A car is traveling at 70 km/h. It then uniformly decelerates to a complete stop in 12 s. Find its acceleration ( in m/s2 ).
Yakvenalex [24]

Answer:

Acceleration will be -1.620m/sec^2

Explanation:

We have given initial speed of the car is 70 km/hr

We know that 1 km = 1000 m

And 1 hour = 3600 sec

So 70km/hr=70\times \frac{1000m}{3600sec}=19.444m/sec

It is given that car stops in 12 sec

So final speed of the car v = 0 m/sec

Time t = 12 sec

From first equation of motion v = u+at

So 0=19.444+a\times 12

a=\frac{-19.444}{12}=-1.620m/sec^2 ( negative sign indicates that speed of the car will constantly decrease )

5 0
3 years ago
Read 2 more answers
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