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3 years ago

A sound wave has frequency 620 Hz and wavelength 10.5 m. What is the speed of sound waves?

Physics

1 answer:

olasank [31]3 years ago

7 0

Answer:

Explanation:

A sound wave in a steel rail has a frequency of 620 Hz and a wavelength of 10.5 m. What is the speed of sound in steel? U f = ? S f = 3 x 108 m/s) / 0.06 m 14 so it will be 14

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How does altitude, distance from the ocean, amount of sunlight, distance from the equator, and ocean currents affect polar clima

drek231 [11]

The altitude is usually low. Tropical places are mainly on the ocean, that's usually why it's so hot. They are usually close to the equator, but not right on it. The tropics get a lot of direct sunlight, so wear that sunscreen! The ocean currents are warm, so they bring along warm water. All of those help make the tropics the way they are.

Hope this helps

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3 years ago

Two moving objects collide and move apart on paths 90 degrees apart. The total momentum after the collision is _______ the total

Tom [10]

A is the correct answer

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3 years ago

tony walks at an average speed of 70m/min from home to school. If the difference between his home and the school is 2100 m, how

finlep [7]

Answer. 30 minutes
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3 years ago

Coherent light of wavelength 525 nm passes through two thin slits that are 4.15Ã—10^(âˆ’2) mm apart and then falls on a screen 7

IRINA_888 [86]

A) 4.7 cm

The formula for the angular spread of the nth-maximum from the central bright fringe for a diffraction from two slits is

$sin \theta=\frac{n \lambda}{d}$

where

n is the order of the maximum

$\lambda$ is the wavelength

$a$ is the distance between the slits

In this problem,

n = 5

$\lambda=525 nm =5.25\cdot 10^{-7} m$

$a=4.15\cdot 10^{-2} mm=4.15\cdot 10^{-5} m$

So we find

$\theta=sin^{-1} (\frac{(5)(5.25\cdot 10^{-7} m)}{4.15\cdot 10^{-5} m})=3.62^{\circ}$

And given the distance of the screen from the slits,

$D=75.0 cm = 0.75 m$

The distance of the 5th bright fringe from the central bright fringe will be given by

$y=D tan \theta = (0.75 m)tan 3.62^{\circ}=0.047 m = 4.7 cm$

B) 8.1 cm

The formula to find the nth-minimum (dark fringe) in a diffraction pattern from double slit is a bit differente from the previous one:

$sin \theta=\frac{(n+\frac{1}{2}) \lambda}{d}$

To find the angle corresponding to the 8th dark fringe, we substitute n=8:

$\theta=sin^{-1} (\frac{(8+\frac{1}{2})(5.25\cdot 10^{-7} m)}{4.15\cdot 10^{-5} m})=6.17^{\circ}$

And the distance of the 8th dark fringe from the central bright fringe will be given by

$y=D tan \theta = (0.75 m)tan 6.17^{\circ}=0.081 m = 8.1 cm$

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3 years ago

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exis [7]

When two tectonic plates collide and form a converging plate boundry, normally one of the plates will slide underneath the other and that is when Subduction occurs.

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3 years ago