Ask question

Ask question

All categories

3 years ago

5

Mike is a runner. Mike runs 200m in 25s; what is his average velocity during the run? assume that units are in m/s. (asap, will

make brainliest)

1 answer:

maw [93]3 years ago

5 0

Velocity is displacement/time
(Displacement is the overall change in distance)

So you’ll want to divide 200 by 25, which should give you:

8 m/s

You might be interested in

What were some benefits to the american television from analog broadcast to digital broadcast?

Elanso [62]

Answer:

nothing no no no

Explanation:

nothing cause no

8 0

3 years ago

Read 2 more answers

A straight segment of a current-carrying wire has a current element IL where I = 2.70 A and L = 3.20 cm i + 4.30 cm j. The segme

myrzilka [38]

The component of the force in negative z-direction is -0.144 N.

The given parameters;

<em>current in the wire, I = 2.7 A</em>
<em>length of the wire, L = (3.2 i + 4.3j) cm</em>
<em>magnetic filed, B = 1.24 i</em>

The force on the segment of the wire is calculated as follows;

$F = ILBsin(\theta)$

where;

<em>θ is the angle wire and magnetic field</em>

<em />

The force on the wire segment will be perpendicular in negative z-direction (applying right hand rule), so there won't be any x and y component of the force.

The angle between the wire and the magnetic field is calculated as follows;

$\theta = tan^{-1} (\frac{y}{x} )\\\\\theta = tan^{-1} (\frac{4.3}{3.2} )\\\\\theta = 53.3 \ ^0$

The magnitude of the wire length is calculated as follows;

$|l | = \sqrt{3.2^2 + 4.3^2} = 5.36 \ cm = 0.0536 \ m$

The component of the force in negative z-direction is calculated as;

$F_z = -ILB sin(\theta)\\\\F_z = -2.7 \times 0.0536 \times 1.24 \times sin(53.3)\\\\F_z = -0.144 \ N$

Thus, the component of the force in negative z-direction is -0.144 N.

Learn more here:brainly.com/question/22719779

6 0

3 years ago

NEED HELP ASAP WILL MARK BRAINLIEST.

-Dominant- [34]

G is the answer for apex vs / Chehhhh

3 0

3 years ago

Where is the potential energy equal to zero?

s2008m [1.1K]

Answer:

im sure your already past this but it's E.

Explanation:

This is because in this case potential energy is linear to height, which means that the higher the more potential energy.

4 0

3 years ago

1000 kg of water initially at 6 m/s runs through a hydro-generator. If the water leaves the generator at velocity of 4 m/s, and

r-ruslan [8.4K]

Answer:

8.00 kJ

Explanation:

The first thing is to determine what quantities are there.

the mass of water = 1 000 kg

initial velocity, u = 6 m/s

final velocity, v = 4 m/s

the generator is operating at 100 % efficiency, so there is no energy loss.

The kinetic energy, Ek is converted to electrical energy, therefore Ek = electrical energy.

The kinetic energy is calculated as follows:

Ek = 1/2 mv²

= 1/2×(1 000)× (4)²

= 8 000 J/s

= 8.00 kJ Ans

4 0

3 years ago