Hello,
Well, Liquids don't have a fixed shape, but they do have a fixed volume.
So the answer would be Neon gas
<span>The answers that are correct from the chart are as follows: 1. From 1975 to 2010, temperatures on earth were higher than normal. Rest option are incorrect. Because, From 1880 to 1940, temperatures on earth were lower and not higher than normal. The 10 warmest years in the time span all did not occur in 1945. The coolest year in the time span occurred 1910.</span>
So, the time needed before you hear the splash is approximately <u>2.06 s</u>.
<h3>Introduction</h3>
Hi ! In this question, I will help you. This question uses two principles, namely the time for an object to fall freely and the time for sound to propagate through air. When moving in free fall, the time required can be calculated by the following equation:
With the following condition :
- t = interval of the time (s)
- h = height or any other displacement at vertical line (m)
- g = acceleration of the gravity (m/s²)
Meanwhile, for sound propagation (without sound reflection), time propagates is the same as the quotient of distance by time. Or it can be formulated by :
With the following condition :
- t = interval of the time (s)
- s = shift or displacement (m)
- v = velocity (m/s)
<h3>Problem Solving</h3>
We know that :
- h = height or any other displacement at vertical line = 19.6 m
- g = acceleration of the gravity = 9.8 m/s²
- v = velocity = 343 m/s
What was asked :
- = ... s
Step by step :
- Find the time when the object falls freely until it hits the water. Save value as
- Find the time when the sound propagate through air. Save value as
- Find the total time
<h3>Conclusion</h3>
So, the time needed before you hear the splash is approximately 2.06 s.
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Answer: 18.02 g/mol
The average mass of one H2O molecule is 18.02 amu. The number of atoms is exact, the number of moles is exact; they do not affect the number of significant figures. The average mass of one mole of H2O is 18.02 grams. This is stated: the molar mass of water is 18.02 g/mol.