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ladessa [460]
3 years ago
8

This chart shows the global temperature anomaly (the difference of the expected temperature and the actual temperature) over a s

pan of 130 years which facts related to climate change does the chart reveal?
(Note: Select all that apply)

1. From 1975 to 2010, temperatures on earth were higher than normal.

2. From 1880 to 1940, temperatures on earth were higher than normal.

3. The 10 warmest years in the time span all occurred in 1945.

4. The coolest year in the time span occurred 1945

5. Temperatures on earth do not fluctuate from from year to year

Physics
2 answers:
Aleks04 [339]3 years ago
6 0
<span>The answers that are correct from the chart are as follows: 1. From 1975 to 2010, temperatures on earth were higher than normal. Rest option are incorrect. Because, From 1880 to 1940, temperatures on earth were lower and not higher than normal. The 10 warmest years in the time span all did not occur in 1945. The coolest year in the time span occurred 1910.</span>
inysia [295]3 years ago
3 0

i just did it and got it correct. the answers are A and C

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An experimenter adds 970 J of heat to 1.75 mol of an ideal gas to heat it from 10.0∘C to 25.0∘C at constant pressure. The gas do
ipn [44]

Answer:

(a) ΔU=747J

(b) γ=1.3

Explanation:

For (a) change in internal energy

According to first law of thermodynamics the change in internal energy is given as

ΔU=Q-W

Substitute the given values

ΔU=970J-223J

ΔU=747J

For(b) γ for the gas.

We can calculate γ by ratio of heat capacities of the gas

γ=Cp/Cv

Where Cp is the molar heat capacity at constant pressure

Cv is the molar heat capacity at constant volume

To calculate γ we first need to find Cp and Cv

So

For Cp

As we know

Q=nCpΔT

Cp=(Q/nΔT)

C_{p}=\frac{970J}{1.75mol*(25^{o}C-10^{o}C )}\\C_{p}=37J/mol.K

From relation of Cv and Cp we know that

Cp=Cv+R

Where R is gas constant equals to 8.314J/mol.K

So

C_{v}=C_{p}-R\\C_{v}=37-8.314\\C_{v}=28.687J/mol.K\\

So

γ=Cp/Cv

γ=[(37J/mol.K) / (28.687J/mol.K)]

γ=1.3

4 0
3 years ago
A 460 W heating unit is designed to operate with an applied potential difference of 120 V (a) By what percentage will its heat o
dybincka [34]

Answer:

(a) = -0.16%

(b) = smaller

Explanation:

given

power = 460 W

potential difference = 120 V

(a) what percentage will   its heat output drop if the applied potential difference drops to 110 V ?

we know p = \frac{v^2}{R} .....................(i)

we need to find change in power

\Delta P = \frac{\Delta (V^2)}{R}  

\Delta P = \frac{2 V \Delta V}{R}..............(ii)

from equations we get

\frac{\Delta P}{P} =  \frac{2 \Delta V}{V}

\frac{\Delta P}{P} = 2 \frac{110 -120}{120}

\frac{\Delta P}{P} =  -2(\frac{10}{120})

\frac{\Delta P}{P} = - 0.16 %

(b)

if we increase temperature resistance will increase and decrease with decrease in temperature and we know power is inversely proportional to resistance so if potential decrease and it would cause drop in power

and due to this increment of heating power resistance will decrease so actual drop in the power would  be smaller

7 0
3 years ago
A refrigerator having a power rating of 350W operates for 12 hours a day. calculate the cost of electrical energy to operate it
rodikova [14]

Answer:

See the answers below.

Explanation:

The cost of energy can be calculated by multiplying each given value, a dimensional analysis must be taken into account in order to calculate the total value of the cost in Rs.

Cost=0.350[kW]*12[\frac{hr}{1day}]*30[days]*4.5[\frac{Rs}{kW*hr} ]=567[Rs]

The fuse can be calculated by knowing the amperage.

P=V*I

where:

P = power = 350 [W]

V = voltage = 240 [V]

I = amperage [amp]

Now clearing I from the equation above:

I=P/V\\I=350/240\\I=1.458[amp]

The fuse should be larger than the current of the circuit, i.e. about 2 [amp]

3 0
3 years ago
A rock weighing 98 newtons is pushed off the edge of a bridge 50 meters above the ground. What was the potential energy of the r
lidiya [134]
Ep = 4900 because Ep = wh
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4 years ago
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Scenario A: A 3 spring is compressed a distance of 1.0 m. Scenario B: A 6 spring is compressed a distance of 0.8 m. Scenario C:
lapo4ka [179]

The CORRECT answer is B

6 0
3 years ago
Read 2 more answers
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