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3 years ago

A dropped ball accelerates as it falls. but a ball rolling on a horizontal surface has zero acceleration because _______.

Physics

2 answers:

svet-max [94.6K]3 years ago

5 0

Answer:

There is no force acting on it.

Explanation:

The dropping ball experiences the force of gravity on it that make sit accelerate towards the ground constantly, if the ball is rolling on a horizontal surface the effect of the gravity will just have an effect on the weight of the ball and the friction, but unless you are applying an external continuos force to that ball it would not experience acceleration.

nordsb [41]3 years ago

4 0

During a fall, the ball experiences an external force which is acted upon by gravity. This gravitation force induces a constant gravitational acceleration on the object equivalent to 9.81 meters per square second. Hence, the dropped ball is accelerating.

On the other hand, the ball does not experience external force hence the acceleration is zero.

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A Chinook salmon can jump out of water with a speed of 6.70 m/s6.70 m/s . How far horizontally dd can a Chinook salmon travel th

aksik [14]

Answer:

R = 3.88 m

Explanation:

As the Chinook salmon leaves the water till it gets back into the water it is performing a projectile motion with the following parameters:

V₀ = Launch Speed = 6.7 m/s

θ = Launch Angle = 29°

R= Range of Projectile= Horizontal Distance Covered by Chinook salmon= ?

The value of the range of a projectile is given by the following formula:

R = (V₀² Sin 2θ)/g

R = [(6.7 m/s)² Sin {(2)(29°)}/(9.8 m/s²)]

R = [(6.7 m/s)² Sin (58°)/(9.8 m/s²)]

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4 years ago

Based on the simple blackbody radiation model described in class, answer the following question. The planets Mars and Venus have

Lera25 [3.4K]

Answer:

The extent of greenhouse effect on mars is $G_m = 87 K$

Explanation:

From the question we are told that

The albedo value of Mars is $A_1 = 0.15$

The albedo value of Mars is $A_2 = 0.15$

The surface temperature of Mars is $T_1 = 220 K$

The surface temperature of Venus is $T_2 = 700 K$

The distance of Mars from the sun is $d_m = 2.28*10^8 \ km = 2.28*10^8* 1000 = 2.28*10^{11} \ m$

The distance of Venus from sun is $d_v = 1.08 *10^{8} \ km = 1.08 *10^{8} * 1000 = 1.08 *10^{11} \ m$

The radius of the sun is $R = 7*10^{8} \ m$

The energy flux is $E = 6.28 * 10^{7} W/m^2$

The solar constant for Mars is mathematically represented as

$T = [\frac{E R^2 (1- A_1)}{\sigma d_m} ]$

Where $\sigma$ is the Stefan's constant with a value $\sigma = 5.6*10^{-8} \ Wm^{-2} K^{-4}$

So substituting values

$T = \frac{6.28 *10^{7} * (7*10^8)^2 * (1-0.15)}{(5.67 *10^{-8}) * (2.28 *10^{11})^2)}$

$T = 307K$

So the greenhouse effect on Mars is

$G_m = T - T_1$

$G_m = 307 - 220$

$G_m = 87 K$

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4 years ago

Measure of how high or low a sound is

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3 years ago

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Which process enables the boy to see over the wall?

den301095 [7]

Answer: yeah it is reflection

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3 years ago

A 20.0-kg rock is sliding on a rough, horizontal surface at 8.00 m/s and eventually stops due to friction. The coefficient of ki

Neporo4naja [7]

Answer:

$a = -1.961\,\frac{m}{s^{2}}$ , $s = 16.318\,m$ , $t = 4.079\,s$

Explanation:

The equations of equilibrium for the rock are:

$\Sigma F_{x} = -\mu_{k}\cdot N = m \cdot a$

$\Sigma F_{y} = N - m\cdot g = 0$

After some algebraic handling, the following expression is found:

$-\mu_{k}\cdot m \cdot g = m \cdot a$

$-\mu_{k}\cdot g = a$

Deceleration experimented by the rock is:

$a = - (0.2)\cdot (9.807\,\frac{m}{s^{2}} )$

$a = -1.961\,\frac{m}{s^{2}}$

The distance travelled by the rock before stopping is:

$s = \frac{(0\,\frac{m}{s} )^{2}-(8\,\frac{m}{s} )^{2}}{2\cdot (-1.961\,\frac{m}{s^{2}} )}$

$s = 16.318\,m$

And the time is:

$t = \frac{0\,\frac{m}{s}-8\,\frac{m}{s}}{(-1.961\,\frac{m}{s^{2}} )}$

$t = 4.079\,s$

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3 years ago

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