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3 years ago

Which description properly describes the plant structures involved in photosynthesis?

Physics

2 answers:

nignag [31]3 years ago

7 0

Answer:

D-Stomata takes in Carbon Dioxide and release oxygen.

Explanation:

The answer is D because...

Photosynthesis rule. Photosynthesis takes in sunlight or carbon dioxide and releases oxygen.

Step one let's look at A Stomata takes in water, sunlight, and carbon dioxide and release oxygen. The reason this is not the answer is because taking in water is not a step in photosynthesis. Photosynthesis is ONLY sunlight or carbon dioxide.
Step two now we shall look at B , Phloem transports water, stomata take in carbon dioxide, and chlorophyll absorbs sunlight. This is not correct because once again water is not a step of photosynthesis and the phloem is NOT apart of the plant in which photosynthesis takes place. Plus the phloem does not transport water. The Xylem does.
Step three let's look at C, Xylem takes in water, sunlight, and carbon dioxide and releases oxygen. This is incorrect because once again photosynthesis does NOT require water or the Xylem. Xylem is the way water transports through out the plant.
Finally Step four. let's look at D. Stomata take in carbon dioxide and release oxygen. This is true because the Stomata acts like a gas change or a door. It takes in the carbon dioxide and the pores open to release oxygen for use mammals to breathe.
Hope this Helped :)

raketka [301]3 years ago

3 0

Answer:

Explanation:

Stomata take in carbon dioxide (i think they realease oxygen too), Phloem transports the glucose throughout the plant, Xylem transports the water and minerals from the roots. If you want me to explain more I can

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Runaway truck ramps are common on mountainous highways in case the brakes fail on large trucks. If a

dusya [7]

Answer:

$W=-21,870,000\ J$

Explanation:

<u>Work and Kinetic Energy </u>

The work an object does due to its motion is equal to the change of its kinetic energy. Being ko and k1 the initial and final kinetic energy respectively and m the mass of the object, then

$W=\Delta k=k_1-k_0$

Since

$\displaystyle k=\frac{mv^2}{2}$

We have

$\displaystyle W=\frac{mv_1^2}{2}-\frac{mv_0^2}{2}$

The truck has a mass of 60,000 kg and is moving at 27 m/s. The runaway truck ramp must stop the truck, so the final speed is 0. Thus

$\displaystyle W=\frac{(60,000)0^2}{2}-\frac{(60,000)(27)^2}{2}$

$W=0-21870000\ J$

$\boxed{W=-21,870,000\ J}$

3 0

3 years ago

If a 6V battery is connected to a light bulb whose resistance is 55,000Ω How much current will flow in the circuit?

notka56 [123]

Answer:

Current, I = 0.000109 Amps

Explanation:

Given the following data;

Voltage = 6V

Resistance = 55,000 Ohms

To find the current flowing through the circuit;

Ohm's law states that at constant temperature, the current flowing in an electrical circuit is directly proportional to the voltage applied across the two points and inversely proportional to the resistance in the electrical circuit.

Mathematically, Ohm's law is given by the formula;

$V = IR$

Where;

V represents voltage measured in voltage.

I represents current measured in amperes.

R represents resistance measured in ohms.

Making current the subject of formula, we have;

$I = \frac {V}{R}$

Substituting into the formula, we have;

$I = \frac {6}{55000}$

Current, I = 0.000109 Amps

5 0

3 years ago

What is the operating life time of a PV Module?

julia-pushkina [17]

Answer:

The industry standard life span is about 25 to 30 years, and that means that some panels installed at the early end of the current boom aren't long from being retired is the operating life time of a PV module .

5 0

2 years ago

if vector u has lenght 70 and direction 40 degrees, and vector v has length 85 and direction 335 degrees what is the length and

Anastaziya [24]

Answer:

Magnitude of resultant = 131.15

Direction of resultant = 3.97°

Explanation:

||u|| = 70

θ = 40°

$\vec{u}_x=||u||cos\theta \\\Rightarrow \vec{u}_x=70cos40=53.62$

$\vec{u}_y=||u||sin\theta \\\Rightarrow \vec{u}_y=70sin40=44.99$

||v|| = 85

θ = 335°

$\vec{v}_x=||v||cos\theta \\\Rightarrow \vec{v}_x=85cos335=77.03$

$\vec{v}_y=||v||sin\theta \\\Rightarrow \vec{v}_y=85sin335=-35.92$

Resultant

$R=\sqrt{R_x^2+R_y^2}\\\Rightarrow R=\sqrt{(\vec{u}_x+\vec{v}_x)^2+(\vec{u}_y+\vec{v}_y)^2}\\\Rightarrow R =\sqrt{(70cos40+85cos335)^2+(70sin40+85sin335)^2}\\\Rightarrow R =131.15$