Answer:
Explanation:
If E₀ is the electric field outside the smaller sphere and r is the radius of larger sphere.
E₀ = kQ/r²
The radius of the larger sphere is 3r and the charge on both sphere is same then the electric field outside the larger sphere is given as
E = kQ/(3r)² = kQ/9r² = 1/9 (kQ/r²)= 1/9 x E₀
hence the correct option is e.
Answer:
Potential energy, E = 25 mgh
Explanation:
Given that,
Mass of the object, m = 5 m
It is lifted to a height of, h = 5 h
It is required to find the potential energy gained by the object. It is given by the product of object's mass, acceleration due to gravity and heigh above ground. It is given by :
E = 25 mgh
So, the potential energy gained by the object is (25 mgh). Hence, this is the required solution.
Umm do u want me to answer this’ll
Answer:
λ = 6.61 x 10⁻⁷ m = 661 nm
Explanation:
From the Young's Double Slit experiment, the the spacing between adjacent bright or dark fringes is given by the following formula:
Δx = λL/d
where,
Δx = fringe spacing = 2.86 mm = 2.86 x ⁻³ m
L = Distance between slits and screen = 2.12 m
d = slit separation = 0.49 mm = 0.49 x 10⁻³ m
λ = wavelength of light = ?
Therefore,
2.86 x 10⁻³ m = λ(2.12 m)/(0.49 x 10⁻³ m)
(2.86 x 10⁻³ m)(0.49 x 10⁻³ m)/(2.12 m) = λ
<u>λ = 6.61 x 10⁻⁷ m = 661 nm</u>
