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soldier1979 [14.2K]
3 years ago
7

Water pressure increases as

Physics
1 answer:
ra1l [238]3 years ago
7 0
My guess is A. depth increases because I know that the deeper you go in the ocean, the higher the water pressure is (which makes it difficult to explore).
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The distance traveled by the scooter driver from 9:00 to 11:00 am is
wlad13 [49]
B is the correct answer
6 0
3 years ago
A 42.6kg lamp is hanging from wires as shown in figure.The ring has negligible mass. Find tensionsT1, T2,T3 if the object is in
IRISSAK [1]

Answer:

T1 = 417.48N

T2 = 361.54N

T3 = 208.74N

Explanation:

Using the sin rule to fine the tension in the strings;

Given

amass = 42.6kg

Weight = 42.6 * 9.8 = 417.48N

The third angle will be 180-(60+30)= 90 degrees

Using the sine rule

W/Sin 90 = T3/sin 30 = T2/sin 60

Get T3;

W/Sin 90 = T3/sin 30

417.48/1 = T3/sin30

T3 = 417.48sin30

T3 = 417.48(0.5)

T3 = 208.74N

Also;

W/sin90 = T2/sin 60

417.48/1 = T2/sin60

T2 = 417.48sin60

T2 = 417.48(0.8660)

T2 = 361.54N

The Tension T1 = Weight of the object = 417.48N

8 0
3 years ago
Alice kicks a soccer ball with a mass of 2 kg. The ball leaves the ground moving 30 meters per second. What is the kinetic energ
sleet_krkn [62]

By using the formula:

• K.E = ½mv²

  • mass, m = 2 kg
  • Velocity, v = 30 m/s

→ K.E = ½ × 2 × (30)² J

→ K.E = (30)² J

→ K.E = 900 J (Answer)

5 0
2 years ago
a positively charged body makes contact with a body. after a while, the charged body becomes neutralised. state 3 main condition
MrRa [10]

Answer:

A body will become positively charged when some electrons will come out from the body.Thus, positive charge is due to deficiency of electrons.

5 0
3 years ago
A pair of eyeglass frames are made of an epoxy plastic (coefficient of linear expansion = 122 ✕ 10-6 °C-1). At room temperature
il63 [147K]

Answer:

The new temperature is  T_1 =  60.78^oC

Explanation:

From the question we are told that

   The coefficient of linear expansion is  \sigma  =  122 *10^{-6} \ ^oC^{-1}

    The temperature is  T  =  20.0 ^oC

    The radius of the frames is r =  2.00 \  cm  = 0.02 \ m

    The new radius is  r_2 =  2.01 \ cm =  0.021 \ m

The change in radius is mathematically represented as

       \Delta r =  r_1 -r

substituting values

       \Delta r =  2.01 - 2.00

       \Delta r =  0.01 \ m

The increase in radius can also be mathematically represented as

     \Delta  r  =  r * \sigma (T_1 -T)

Where T_1 is the the new temperature , making it the subject we have

      T_1 =  \frac{\Delta  r}{r * \sigma  } + T

substituting value  

     T_1 =  \frac{0.01}{2.01 *122*10^{-6}  } + 20

    T_1 =  60.78^oC

5 0
4 years ago
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