Answer:0.1759 v
Explanation:
Intensity of wave at receiver end is
I=
I=
I=
Amplitude of electric field at receiver end
Amplitude of induced emf
=
=
=
A 1 kg ball moving horizontally to the right at 3 m/s strikes a wall and rebound, moving horizontally to the left at the same ve
1 answer:
Answer:
The magnitude of the change in linear momentum of the ball is 6 kg-m/s.
Explanation:
Given that,
Mass of the ball, m = 1 kg
Initial sped of the ball, u = 3 m/s
It strikes a wall and rebound, moving horizontally to the left at the same velocity of 3 m/s, v = -3 m/s
The magnitude of the change in linear momentum of the ball is given by :
So, the magnitude of the change in linear momentum of the ball is 6 kg-m/s.
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Answer
In this question we have given,
Height of plane, h1=2000m
Height at which charge concentration is 40C, h2=3000m
Height at which charge concentration is -40C, h3=1000m
charge concentaration, q1=40C
charge concentaration, q2=-40C
let the charge concentrations at height h2 and h3 as point charges
Now we will first find the electric feild on plane due to positive charge q1=40
Here k=8.98755*10^9N.m^2/C^2
q1=40C
put values of k, q1 , h1 and h2 in equation 1
\\
V/m[/tex]
similarly electric feild due to negative charge q2=-40
\\
Total electric feild E at the aircraft is given as
...............(2)
Put values of E1 and E2 in equation2
therefore s Total electric feild E at the aircraft is E= 719004V/m