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Lunna [17]
3 years ago
5

A 1 kg ball moving horizontally to the right at 3 m/s strikes a wall and rebound, moving horizontally to the left at the same ve

locity of 3 m/s. What is the magnitude of the change in linear momentum of the ball?
Physics
1 answer:
Airida [17]3 years ago
3 0

Answer:

The magnitude of the change in linear momentum of the ball is 6 kg-m/s.

Explanation:

Given that,

Mass of the ball, m = 1 kg

Initial sped of the ball, u = 3 m/s

It strikes a wall and rebound, moving horizontally to the left at the same velocity of 3 m/s, v = -3 m/s

The magnitude of the change in linear momentum of the ball is given by :

p=m(v-u)\\\\p=1\ kg\times (-3-3)\\\\p=-6\ kg-m/s

So, the magnitude of the change in linear momentum of the ball is 6 kg-m/s.

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The energy from 0.015 moles of octane was used to heat 250 grams of water. The temperature of the water rose from 293.0 K to 371
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Now put all the given values in the above formula, we get:

\Delta H=\frac{-81719J}{0.015mole}

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