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Lunna [17]
4 years ago
5

A 1 kg ball moving horizontally to the right at 3 m/s strikes a wall and rebound, moving horizontally to the left at the same ve

locity of 3 m/s. What is the magnitude of the change in linear momentum of the ball?
Physics
1 answer:
Airida [17]4 years ago
3 0

Answer:

The magnitude of the change in linear momentum of the ball is 6 kg-m/s.

Explanation:

Given that,

Mass of the ball, m = 1 kg

Initial sped of the ball, u = 3 m/s

It strikes a wall and rebound, moving horizontally to the left at the same velocity of 3 m/s, v = -3 m/s

The magnitude of the change in linear momentum of the ball is given by :

p=m(v-u)\\\\p=1\ kg\times (-3-3)\\\\p=-6\ kg-m/s

So, the magnitude of the change in linear momentum of the ball is 6 kg-m/s.

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A roller coaster is at the top of a 102 m hill and a mass of 120 kg. The coaster (at this
dybincka [34]
  • Height=h=102m
  • Mass=m=120g
  • Acceleration due to gravity=g=10m/s^2

\\ \sf\longmapsto P.E=mgh

  • P E means potential energy

\\ \sf\longmapsto P.E=102(120)(10)

\\ \sf\longmapsto P.E=122400J

7 0
3 years ago
A rocket is fired vertically upwards with initial velocity 92 m/s at the ground level. Its engines then fire and it is accelerat
Readme [11.4K]

Answer:

The rocket above the ground is in 44 sec.

Explanation:

Given that,

Initial velocity = 92 m/s

Acceleration = 4 m/s²

Altitude = 1200 m

Suppose, How long was the rocket above the ground?

We need to calculate the time

Using equation of motion

s=ut-\dfrac{1}{2}at^2

Put the value into the formula

1200=92t+\dfrac{1}{2}\times4t^2

2t^2+92-1200=0

t=10\ sec

We need to calculate the velocity

Using equation of motion

v=u+at

Put the value into the formula

v=92+4\times10

v=132\ m/s

When the rocket hits the ground,

Then, h'=0

We need to calculate the time

Using equation of motion

h'=h+ut-\dfrac{1}{2}at^2

Put the value into the formula

0=1200+132t-\dfrac{1}{2}\times9.8t^2

4.9t^2-132t-1200=0

t=34\ sec

When the rocket is in the air it is the sum of the time when it reaches 1000 m and the time when it hits the ground

So, the total time will be

t'=34+10

t'=44\ sec

Hence, The rocket above the ground is in 44 sec.

7 0
4 years ago
The perceived pitch of a tone is largely determined by its
soldier1979 [14.2K]

The perceived pitch of a tone is largely determined by its frequency

<h3>What is  frequency ?</h3>

The frequency of a repeated event is its number of instances per unit of time. In some cases, it is also referred to as temporal frequency or ordinary frequency to underline differences with spatial and angular frequencies, respectively. One (event) per second is equal to one hertz (Hz), which is how frequency is stated.

The period is the reciprocal of the frequency since it is the length of time for one cycle in a repeating occurrence. If a heart beats 120 times per minute (2 hertz), for instance, its period, T—the space between beats—is half a second. In science and engineering, frequency is a crucial metric for describing the temporal rate of change seen in oscillatory systems.

To learn more about frequency  from the given link:

brainly.com/question/27216648

#SPJ4

3 0
2 years ago
How many turns should a 10-cm long solenoid have if it is to generate a 1.5 x 10-3 t magnetic field on 1.0 a of current?
stepan [7]

We can answer this problem using Ampere’s Law:

<span>Bh = μoNI </span>

Where:

B = Magnetic Field

h = coil length

<span>μo = permeability =4π*10^-7 T·m/A </span>

N = number of turns

I = current

It is given that B=0.0015T, I=1.0A, h=10 cm = 0.1m<span>

Use Ampere's law to find # turns: 
Which can be rewritten as: 
<span>N = Bh/μoI </span>
N = (0.0015)(0.1)/(4π*10^-7)(1.0) 
N = 119.4 

</span>

<span>Answer: 119.4 turns</span>

3 0
3 years ago
While a balloon is being filled, if the temperature of the air in the balloon decreases, what happens to its volume?
Ugo [173]
Why is it always balloons?
anyways so the balloon volume goes somewhere else when it shrinks because the balloon is losing air i think
4 0
4 years ago
Read 2 more answers
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