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Lunna [17]
3 years ago
5

A 1 kg ball moving horizontally to the right at 3 m/s strikes a wall and rebound, moving horizontally to the left at the same ve

locity of 3 m/s. What is the magnitude of the change in linear momentum of the ball?
Physics
1 answer:
Airida [17]3 years ago
3 0

Answer:

The magnitude of the change in linear momentum of the ball is 6 kg-m/s.

Explanation:

Given that,

Mass of the ball, m = 1 kg

Initial sped of the ball, u = 3 m/s

It strikes a wall and rebound, moving horizontally to the left at the same velocity of 3 m/s, v = -3 m/s

The magnitude of the change in linear momentum of the ball is given by :

p=m(v-u)\\\\p=1\ kg\times (-3-3)\\\\p=-6\ kg-m/s

So, the magnitude of the change in linear momentum of the ball is 6 kg-m/s.

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What are stepdown transformers used for
lesya692 [45]

Answer:

Step down transformers are used in power adaptors and rectifiers to efficiently decrease the voltage. They are also used in electronic SMPS.

Explanation:

pls mark me as brainlist

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7 0
2 years ago
What is the mass of a large ship that has a momentum of 1.60x10^9 kg*m/s and is moving at a velocity of 10m/s?
Elden [556K]

Answer:

160000000 kg.

Explanation:

p=mv

p=1.6x10^9

v=10m/s

rearrange and substitute:

(1.6x10^9)=m(10)

m=(1.6x10^9)/10

m= 1.6x10^8 kg.

7 0
3 years ago
Explain how an electrical current is produced.
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Electric current can be generated by moving a metal wire through a magnetic field It is also different than static electricity, which is the accumulation of charges on a surface. Electric generators rotate a coil of wires through a magnetic field.
5 0
3 years ago
Read 2 more answers
An object of mass m is lowered at constant velocity at the end of a string of negligible mass. As it is lowered a vertical dista
bezimeni [28]

Answer:

Mechanical would have been conserved if only the force of gravity (the weight of the object does work on the system). The tension force does work also on the system but negative work instead. The net force acting of the system is zero since the upward tension in the string suspending the object is equal to the weight of the object but acting in the opposite direction. As a result they cancel out. In the equation above the effect of the tension force on the object has been neglected or not taken into consideration. For the mechanical energy E to be conserved, the work done by this tension force must be included into the equation. Otherwise it would seem as though energy has been generated in some manner that is equal in magnitude to the work done by the tension force.

The conserved form of the equation is given by

E = K + Ug + Wother.

In this case Wother = work done by the tension force.

In that form the total mechanical energy is conserved.

5 0
3 years ago
PLEASE HELP!!
anyanavicka [17]

Answer:

The boat will move in the direction of the force exerted.

Explanation:

To describe the motion of the boat, we shall first obtain the net force acting on the boat. This can be obtained as illustrated below:

From the question given above, the following data were obtained:

Force exerted (Fₑ) = 300 N

Resistive force (Fᵣ) = 250 N

Net force (Fₙ) =?

Fₙ = Fₑ – Fᵣ

Fₙ = 300 – 250

Fₙ = 50 N

Thus, the net force acting on the boat is 50 N in the direction of the force exerted.

Since the net force is in the direction of the force exerted, the boat will move in the direction of the force exerted..!

5 0
3 years ago
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