Answer:
Therefore,
a) ![\dfrac{N_{1}}{N_{2}}=\dfrac{10}{1}](https://tex.z-dn.net/?f=%5Cdfrac%7BN_%7B1%7D%7D%7BN_%7B2%7D%7D%3D%5Cdfrac%7B10%7D%7B1%7D)
b) I₂ = 2.55 Ampere
c) Power = 30.6 Watts
d) R₁ = 470.58 ohms.
Explanation:
Given:
Let the primary voltage be,
![V_{1}=120\ V](https://tex.z-dn.net/?f=V_%7B1%7D%3D120%5C%20V)
Secondary Voltage,
![V_{2}=12\ V](https://tex.z-dn.net/?f=V_%7B2%7D%3D12%5C%20V)
Secondary Resistance,
![R_{2}=4.7\ ohms](https://tex.z-dn.net/?f=R_%7B2%7D%3D4.7%5C%20ohms)
To Find:
a) ![\dfrac{N_{1}}{N_{2}}=?](https://tex.z-dn.net/?f=%5Cdfrac%7BN_%7B1%7D%7D%7BN_%7B2%7D%7D%3D%3F)
b) I₂ = ?
c) Power = ?
d) R₁ = ?
Solution:
The ratio of primary to secondary turns of the transformer, is the ratio of primary to secondary Voltage and is given by,
![\dfrac{N_{1}}{N_{2}}=\dfrac{V_{1}}{V_{2}}](https://tex.z-dn.net/?f=%5Cdfrac%7BN_%7B1%7D%7D%7BN_%7B2%7D%7D%3D%5Cdfrac%7BV_%7B1%7D%7D%7BV_%7B2%7D%7D)
Substituting the values we get
![\dfrac{N_{1}}{N_{2}}=\dfrac{120}{12}=\dfrac{10}{1}](https://tex.z-dn.net/?f=%5Cdfrac%7BN_%7B1%7D%7D%7BN_%7B2%7D%7D%3D%5Cdfrac%7B120%7D%7B12%7D%3D%5Cdfrac%7B10%7D%7B1%7D)
For, rms current for the secondary supply,
![I_{2}=\dfrac{V_{2}}{R_{2}}](https://tex.z-dn.net/?f=I_%7B2%7D%3D%5Cdfrac%7BV_%7B2%7D%7D%7BR_%7B2%7D%7D)
Substituting the values we get
![I_{2}=\dfrac{12}{4.7}=2.55\ Ampere](https://tex.z-dn.net/?f=I_%7B2%7D%3D%5Cdfrac%7B12%7D%7B4.7%7D%3D2.55%5C%20Ampere)
Now for average power at load,
![Power=V_{2}\times I_{2}](https://tex.z-dn.net/?f=Power%3DV_%7B2%7D%5Ctimes%20I_%7B2%7D)
Substituting the values we get
![Power=12\times 2.55=30.6\ Watts](https://tex.z-dn.net/?f=Power%3D12%5Ctimes%202.55%3D30.6%5C%20Watts)
Now for resistance connected directly across the source line Power will remain same,
![Power=\dfrac{(V_{1})^{2}}{R_{1}}](https://tex.z-dn.net/?f=Power%3D%5Cdfrac%7B%28V_%7B1%7D%29%5E%7B2%7D%7D%7BR_%7B1%7D%7D)
Substituting the values we get
![R_{1}=\dfrac{(V_{1})^{2}}{Power}=\dfrac{14400}{30.6}=470.58\ ohms](https://tex.z-dn.net/?f=R_%7B1%7D%3D%5Cdfrac%7B%28V_%7B1%7D%29%5E%7B2%7D%7D%7BPower%7D%3D%5Cdfrac%7B14400%7D%7B30.6%7D%3D470.58%5C%20ohms)
Therefore,
a) ![\dfrac{N_{1}}{N_{2}}=\dfrac{10}{1}](https://tex.z-dn.net/?f=%5Cdfrac%7BN_%7B1%7D%7D%7BN_%7B2%7D%7D%3D%5Cdfrac%7B10%7D%7B1%7D)
b) I₂ = 2.55 Ampere
c) Power = 30.6 Watts
d) R₁ = 470.58 ohms.
Answer:
960J
Explanation:
Given parameters:
Force = 120N
Distance = 8m
Unknown:
Work required = ?
Solution:
The work done by a body is the force applied to move a body in a specific direction.
Work done = Force x distance
Insert the parameters and solve;
Work done = 120 x 8 = 960J
Answer:
C. Talk test
Explanation:
The talk test would be readily available to me at the the least cost.
The talk test is about the easiest way that one can monitor intensity as they exercise. Because the only thing needed here is the ability to talk and to breathe.
The intensity lies on if one can talk and breathe at the same time. The harder one exercises, the more breathless they become and they find it difficult to talk.
<span>So we want to know what does occur when light is refracted from a rough and unpolished surface. The correct answer is A. the original pattern of the light is distorted because rough and unpolished surfaces dissipate light in all directions so we cant get a clear image.</span>
Answer:
Explanation:
In the process of convection, first the molecules of substance gets heat and becomes heated. As the molecules heated, their density decreases and hence they rises up. And the molecules which are cooler, they fall and comes in contact of higher temperature and then they rises up. the process repeats itself until the entire liquid heated uniformly.