(a)
mass of the car: m=950 kg
Initial speed:
Final speed: (the car comes to rest)
distance:
We can find the acceleration by using the following SUVAT equation:
Re-arranging it and replacing the numbers, we find the acceleration
So now we can calculate the force using Newton's second law:
And the negative sign means the force is applied against the direction of motion.
(b)
In this case, the distance is different:
so, the acceleration in this case is
And so, the force applied in this case is
which is much larger than the force exerted in the previous exercise.
Answer:
The fact of light and radio waves being deflected by passing obliquely through an interface between one medium or another.
Answer:
201.06m/s
Explanation:
The solve this problem, we must understand that momentum must be conserved.
This implies that the starting momentum must be the same as the ending momentum. Since we are dealing with an inelastic collision:
Momentum of Plane + Momentum of truck = Momentum of plane + truck
Mp x Vp + Mt x Vt = V(Mp + Mt)
M is the mass
V is the velocity
t is truck
p is the plane
(540000 x 210) + (24000 x 0) = V (540000+24000)
113400000 = 564000V
V = 201.06m/s
Answer:
Force of friction is (-30 N).
Explanation:
The force applied on the box across the floor is 30 N.
The force of gravity is (-8 N) and the the normal force is 8 N.
It is based on Newton's third law of motion. Newton's third law of motion states that the force acting on object 1 to object 2 is equal in magnitude of the force from object 2 to 1 but in opposite direction.
Here there is force of 30 N is applied in horizontal direction. The frictional force act in opposite direction. So, the force of friction is -30 N so that box across the floor.
The elementary unit of charge (the charge on one electron) = 1.6 x 10^-19 coulomb.
1 coulomb = the charge on 6.25 x 10^18 electrons
10 coulombs = the charge on 6.25 x 10^19 electrons