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ICE Princess25 [194]
4 years ago
15

A force of 150 N is applied to a 25 cm2 piston in a hydraulic machine. What is the area of a larger piston if the force availabl

e in it is 450 N?
Physics
1 answer:
Colt1911 [192]4 years ago
8 0

Answer:

The answer to your question is 75 cm²

Explanation:

To solve this problem, we need to use the Pascal's principle that states that the pressure in a point is equal to the pressure in a second point.

                  \frac{F1}{A1} = \frac{F2}{A1}

Process

1.- Solve for A2

                  A2 = \frac{F2A1}{F1}

2.- Substitution

                  A2 = \frac{450N x 25 cm2}{150 N}

3.- Simplification and result

                  A2 = \frac{11250}{150}

                         A2 = 75 cm²

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In the eastern US, hurricanesusually form over the warm waters of the Caribbean Sea and travel north. When they are over the col
garik1379 [7]

Answer:

Less powerful

Explanation:

Hurricanes rely on warm water. It sucks heat energy from the water to use for fuel. Warmer water means more moisture, which also mean a bigger and/or stronger hurricane. The North Atlantic is definitely much colder than the Caribbean so the hurricane will not have much fuel.

Have a great day!

8 0
3 years ago
Name the type of radiation that links satellite to earth
lianna [129]

Answer: I don't know sorry.

Explanation:

8 0
3 years ago
What will be the temperature reading in Fahrenheit scale whe eading is 310 k?​
Otrada [13]

The temperature reading in Fahrenheit scale when reading 310 K is  98.6F

<h3>What is temperature?</h3>

Temperature is the degree of hotness or coldness of the object.

Given is a temperature in Kelvin scale = 310 K

Temperature on centigrade scale = 310 -273 = 37°C

Temperature conversion from Centigrade to Fahrenheit is

C/5 = F -32/9

Plug the value, we get

37/5 = F-32/9

66.6 = F -32

F = 32+66.6 =

F = 98.6

Thus, the temperature of 310 K in Fahrenheit is 98.6F.

Learn more about temperature.

brainly.com/question/11464844

#SPJ1

5 0
2 years ago
Un campo eléctrico es creado por una carga eléctrica de 5 microcoulomb, a 35 cm se coloca una carga de prueba la cual es atraída
Sidana [21]

Answer:

Supongo que queremos determinar la carga de la carga de prueba.

Sabemos que la fuerza culombiana entre dos cargas q₁ y q₂, separadas por una distancia R, está dada por:

F = k_c*\frac{|q_1*q_2|}{R^2}

Aislandolo para una de las cargas, obtenemos:

\frac{F*R^2}{kc*|q_1|} =|q_2|

En este caso sabemos:

fuerza atractiva, por lo que los signos de las cargas son opuestos.

q₁  = 5 mC

R = 35cm

F = 1.5 N

Kc = 9*10^9 N*m^2/C^2

Un primer paso, seria reescribir todos los valores en las mismas unidades.

Sabiendo que:

100cm = 1m

R = 35cm = (35/100) m = 0.35m

Y sabiendo que:

1mc = 1*10^(-6) C

Entonces:

q₁  = 5 mC = 5*1*10^(-6) C = 5*10^(-6) C

Ahora podemos reemplazar esos valores en la ecuación de la fuerza, para obtener el valor de la otra carga:

\frac{15N*(0.35m)^2}{(9*10^9 N*m^2/C^2)*5*10^{-6}C} =|q_2| = 4.08*10^{-5} C

Y recordar que las cargas tienen signo opuesto, entonces la carga de la carga de prueba es:

q₂ = -4.08*10^-5 C

8 0
3 years ago
How do you not know your asleep till your awake lol
ozzi

Answer:

i think since our body is relaxed and our minds are relaxing. i'm not completely sure but i just think that we are kinda partially unconscious in a sense, but i don't really know. i'm not a professional or anything so i guess i don't have a lot of experience in these types of things lol.

Explanation:

anyways,

have a good day !

~mina-san

6 0
3 years ago
Read 2 more answers
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