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2 years ago

Which of the balls will exert the smallest force on object A?Why

Physics

1 answer:

olganol [36]2 years ago

6 0

The 1kg ball would exert the smallest force.

As force = mass x gravity, this means that the smaller the mass (kg), the lesser the force.

When the mass is lighter (1kg):

Force = mass x gravity
Force = 1 x 9.8
Force = 9.8N

Compared to when the mass is heavier (10kg)

Force = mass x gravity
Force = 10 x 9.8
Force = 98N

Where this proves that the lighter the mass, the smaller the force exerted.

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What a neurology professor does = _______ brains

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That’s really easy ask your teacher and also peace happy

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2 years ago

The leaning tower of Pisa is about 56 meters tall. A ball released from the top takes 3.4 seconds to reach the ground. The final

geniusboy [140]

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3 years ago

Read 2 more answers

A long wire carrying a 5.0 A current perpendicular to the xy-plane intersects the x-axis at x= - 2.0 cm . A second, parallel wir

mario62 [17]

Answer:

a . 0.35cm

b. 11.33cm

Explanation:

a. Given both currents are in the same direction, the null point lies in between them. Let x be distance of N from first wire, then distance from 2nd wire is 4-x

#For the magnetic fields to be zero,the fields of both wires should be equal and opposite.They are only opposite in between the wires:

$\frac{\mu_oi_1}{2\pi x}=\frac{\mu_oi_2}{2\pi(4-x)}\\\\5/x=\frac{3.5}{4-x}\\\\x=2.35cm\\\\N=2.35-2=0.35cm$

Hence, for currents in same direction, the point is 0.35cm

b. Given both currents flow in opposite directions, the null point lies on the other side.

#For the magnetic fields to be zero,the fields of both wires should be equal and opposite.They are only opposite in outside the wires:

Let x be distance of N from first wire, then distance from 2nd wire is 4+x:

$\frac{\mu_oi_1}{2\pi(4+ x)}=\frac{\mu_oi_2}{2\pi x}\\\\5/(4+x)=\frac{3.5}{x}\\\\x=9.33cm\\\\N=9.33+2=11.33cm$

Hence, if currents are in opposite directions the point on x-axis is 11.33cm

8 0

3 years ago

Clay Matthews, a linebacker for the Green Bay Packers, can reach a speed of 10.0 m/s. At the start of a play, Matthews runs down

MA_775_DIABLO [31]

Answer:

a) D_ total = 18.54 m, b) v = 6.55 m / s

Explanation:

In this exercise we must find the displacement of the player.

a) Let's start with the initial displacement, d = 8 m at a 45º angle, use trigonometry to find the components

sin 45 = y₁ / d

cos 45 = x₁ / d

y₁ = d sin 45

x₁ = d sin 45

y₁ = 8 sin 45 = 5,657 m

x₁ = 8 cos 45 = 5,657 m

The second offset is d₂ = 12m at 90 of the 50 yard

y₂ = 12 m

x₂ = 0

total displacement

y_total = y₁ + y₂

y_total = 5,657 + 12

y_total = 17,657 m

x_total = x₁ + x₂

x_total = 5,657 + 0

x_total = 5,657 m

D_total = 17.657 i^+ 5.657 j^ m

D_total = Ra (17.657 2 + 5.657 2)

D_ total = 18.54 m

b) the average speed is requested, which is the offset carried out in the time used

v = Δx /Δt

the distance traveled using the pythagorean theorem is

r = √ (d1² + d2²)

r = √ (8² + 12²)

r = 14.42 m

The time used for this shredding is

t = t1 + t2

t = 1 + 1.2

t = 2.2 s

let's calculate the average speed

v = 14.42 / 2.2

v = 6.55 m / s

8 0

3 years ago

The diameter of an atom is 1.1×10−10m and the diameter of its nucleus is 1.0×10−14m. Part A What percent of the atom's volume is

77julia77 [94]

To solve this problem we will use the basic concept given by the Volume of a sphere with which the atom approaches. The fraction in percentage terms would be given by the division of the total volume of the nucleus by that of the volume of the atom, that is,

$\% Percent = \frac{V_{nucleus}}{V_{atom}}*100$