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Vaselesa [24]
3 years ago
14

Mary spins a ball in a horizontal circle on a massless string. Karen has a similar ball but

Physics
1 answer:
Yuliya22 [10]3 years ago
3 0

Answer: d

Explanation:

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1 Beth isn't a very good student. She's very ......<br>A rude<br>B lazy<br>C clever​
kap26 [50]

Answer:

c she's very clever

Explanation:

5 0
3 years ago
Read 2 more answers
According to the nebular theory, what early event eventually led to the formation of our solar system?​
qaws [65]

Answer:Solar system formed about 4.6 billion year ago, when gravity pulled together low-density cloud of interstellar gas and dust (called a nebula)(movie). The Orion Nebula, an interstellar cloud in which star systems and possibly planets are forming. Initially the cloud was about several light years across.

Explanation:

4 0
3 years ago
Consider the electronic elements that are cooled by forced convection in Problem 6.31. The cooling system is designed and tested
Stella [2.4K]

Answer:

surface temperature of the chip located 120 mm Ts=42.5°C

surface temperature of the chip in Mexico Ts=46.9°C

Explanation:

from the energy balance equation we have to:

q=E=30W

from Newton´s law:

Ts=Tα+(q/(h*A)), where A=l^2

N=h/k=0.04*(Vl/V)^0.85*Pr^1/3

data given:

l=0.12 m

v=10 m/s

k=0.0269 W/(m*K)

Pr=0.703

Replacing:

h=0.04*(0.0269/0.12)*(10*0.12)/((16*69x10^-6))^0.85*(0.703^1/3) = 107 W/m^2*K

The surface temperature at sea level is equal to:

Ts=25+(30x10^-3/107*0.004^2)=42.5°C

h=0.04*(0.0269/0.12)*((10*0.12)/(21*81x10^-6))^0.85*(0.705^1/3)=85.32 W/(m*K)

the surface temperature at Mexico City is equal to:

Ts=25+(30x10^-3/85.32*0.004^2)=46.9°C

8 0
3 years ago
PLEASE HELP ME
son4ous [18]

Answer:

synthesis is correct answer.

6 0
3 years ago
A baseball of radius r = 5.2 cm is at room temperature T = 20.8 C. The baseball has emissivity of ε = 0.86 and the Stefan-Boltzm
Marrrta [24]

Answer:

P = 12.37 \frac{J}{s} = 12.37 Watts

Explanation:

Previous concepts

The Thermal radiation is one of "3 mechanisms who allows to bodies exchange energy".

The thermal radiation formula is given by:

\frac{P}{A} = \epsilon \sigma T^4

Where \sigma = 5.67 x10^{-8} \frac{J}{sm^2 K^4}

If we solve for P we got:

P = A \epsilon \sigma T^4

Since we have a baseball ball considered as a sphere the superficial area is given by:

A = 4\pi r^2

Solution to the problem

And if we replace this into our equation of P we got:

P = (4\pi r^2) \epsilon \sigma T^4

And we can reorder this like that:

P = 4 \epsilon \pi \sigma r^2 T^4

We can convert the radius to meters and we got:

r= 5.2 cm*\frac{1m}{100 cm}=0.052 m

Now we can convert the temperature to Kelvin and we got:

T = 20.8 +273.15 = 293.95 K

\epsilon = 0.86 the emissivity given

And now we can replace into the formula for P and we got:

P = 4*0.86*\pi *(5.67x10^{-8} \frac{J}{s m^2 K^4}) (0.052m)^2 (293.95 K)^4

P = 12.37 \frac{J}{s} = 12.37 Watts

6 0
3 years ago
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