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barxatty [35]
3 years ago
13

Cho các máy cắt sử dụng trong công nghiệp có ký hiệu trên nhãn thiết bị: C350; B500. Hãy tính dòng điện bảo vệ ngắn mạch và dòng

điện bảo vệ quá tải của từng thiết bị?
Physics
1 answer:
solniwko [45]3 years ago
3 0

Answer:

ask in the English then I can help you

Explanation:

please mark me as brain list

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Does organisms get rid of waste
Strike441 [17]
Bacteria get rid of waste through their semi-permeable membrane by diffusion. The waste is pushed out of the organism in the form of liquid or gas. The waste released by bacteria is usually toxic and is what makes people sick.
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When an object is in a. Gravitas field it has energy in its
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Potential energy because of the positions on gravatational field
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At a certain distance from the center of the Earth, a 0.4-kg object has a weight of 2.0 N. (a) Find this distance. (b) If the ob
Alika [10]

Answer:

a) The distance of the object from the center of the Earth is 8.92x10⁶ m.

b) The initial acceleration of the object is 5 m/s².

Explanation:

a) The distance can be found using the equation of gravitational force:

F = \frac{GMm}{r^{2}}

Where:

G: is the gravitational constant = 6.67x10⁻¹¹ Nm²/kg²

M: is the Earth's mass =  5.97x10²⁴ kg  

m: is the object's mass = 0.4 kg

F: is the force or the weight = 2.0 N    

r: is the distance =?

The distance is:

r = \sqrt{\frac{GMm}{F}} = \sqrt{\frac{6.67 \cdot 10^{-11} Nm^{2}/kg^{2}*5.97 \cdot 10^{24} kg*0.4 kg}{2.0 N}} = 8.92 \cdot 10^{6} m      

Hence, the distance of the object from the center of the Earth is 8.92x10⁶ m.

         

b) The initial acceleration of the object can be calculated knowing the weight:              

W = ma                                                  

Where:            

W: is the weight = 2 N

a: is the initial acceleration =?          

a = \frac{W}{m} = \frac{2 N}{0.4 kg} = 5 m/s^{2}

Therefore, the initial acceleration of the object is 5 m/s².

           

I hope it helps you!    

4 0
3 years ago
You drop an ice cube into an insulated bottle full of water and wait for the ice cube to completely melt. The ice cube initially
AVprozaik [17]

Answer:

T_{f}  = 17º C

Explanation:

This is a calorimetry problem, where heat is yielded by liquid water, this heat is used first to melt all ice, let's look for the necessary heat (Q1)  

Let's reduce the magnitudes to the SI system  

      Ice m = 80.0 g (1 kg / 1000 g) = 0.080 kg  

            L = 3.33 105 J / kg  

Water  M = 860 g = 0.860 kg  

           c_{e} = 4186 J / kg ºC

    Q₁ = m L  

     Q₁ = 0.080 3.33 10⁵

     Q₁ = 2,664 10⁴ J

Now let's see what this liquid water temperature is when this heat is released  

      Q = M c_{e} ΔT = M c_{e} (T₀₁ -T_{f1})  

      Q₁ = Q  

     T_{f1} = T₀₁ - Q / M ce  

     T_{f1} = 26.0 - 2,664 10⁴ / (0.860 4186)  

     T_{f1} = 26.0 - 7.40  

     T_{f1} = 18.6 ° C  

The initial temperature of water that has just melted is T₀₂ = 0ª  

The initial temperature of the liquid water is T₀₁= 18.6  

     m c_{e} T_{f} + M c_{e} T_{1} = M c_{e} T₀₁ - m c_{e} T₀₂o2  

         T_{f} = (M To1 - m To2) / (m + M)  

         T_{f} = (0.860 18.6 - 0.080 0) / (0.080 + 0.860)  

T_{f} = 17º C

 

gg

4 0
3 years ago
What is the wavelength in nanometers of light when the energy is 1. 91 × 10^6 j for a mole of photons?.
JulijaS [17]

The wavelength in nanometers of light when the energy is 1. 91 × 10^6 j for a mole of photons is <u>62. 8 nm.</u>

Wavelength is the distance among the same points (adjacent crests) within the adjoining cycles of a waveform signal propagated in space or along a cord. In wi-fi structures, this period is typically specified in meters (m), centimeters (cm), or millimeters (mm).

The wavelength is the distance between wave crests, and it is going to be the same for troughs. The frequency is the variety of vibrations that skip over a given spot in one 2nd, and it's far measured in cycles consistent with the second (Hz) (Hertz).

Frequency is the ratio of pace and wavelength in relation to speed. In comparison, wavelength refers to the ratio of pace and frequency. Audible sound waves are characterized by way of a frequency range of 20 to 20 kHz. In contrast, the variety of wavelengths of visible light is from four hundred to seven hundred nm.

<u>calculation:-</u>

*E=hc/λ

1.91 × 10^6 J = (6.62610⁻³⁴) (3.00*10⁸) / λ

λ= (6.62610⁻³⁴) (3.00*10⁸) / 1.91 × 10⁶ J

λ= 1.0410⁻³¹× 10⁻⁹ × 6.022*10²³

 =<u> 62. 8 nm </u>

Learn more about wavelength here:-brainly.com/question/10728818

#SPJ4

6 0
1 year ago
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