the answer i got was -28 and i used a calculator
Answer:
f(2) = 15.5
f(3) = 18
f(4) = 20.5
f(5) = 23
f(6) = 25.5
g(2) = 64
g(3) = 96
g(4) = 128
g(5) = 160
g(6) = 192
Step-by-step explanation:
plug it all in to the equations
I believe 4/13 is the bigger number because 0.36>0.3
I suggest using a calculator to check but I believe 3/10 is the rational number because it terminates and doesn't repeat
Answer:
Kindly check explanation
Step-by-step explanation:
H0 : μ = 5500
H1 : μ > 5500
The test statistic assume normal distribution :
Test statistic :
(Xbar - μ) ÷ s/sqrt(n)
(5625.1 - 5500) ÷ 226.1/sqrt(15) = 2.1429 = 2.143
Pvalue from test statistic :
The Pvalue obtained using the calculator at df = 15 - 1 = 14 is 0.025083
α = 0.05
Since ;
Pvalue < α
0.025083 < 0.05 ; Reject H0
The confidence interval :
Xbar ± Tcritical * s/sqrt(n)
Tcritical at 95% = 1.761 ;
margin of error = 1.761 * 226.1/sqrt(15) = 102.805
Lower boundary : (5625.1 - 102.805) = 5522.295
(5522.295 ; ∞)
The hypothesized mean does not occur within the constructed confidence boundary. HENCE, there is significant eveidbce to support the claim that the true mean life of a biomedical device is greater than 5500
