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2 years ago

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One rectangle has a base of 12 inches and an altitude of 6 inches. The other has a base of 10 inches and an altitude of 5 inches

. what is the ratio of the first rectangle to the second?

1 answer:

guajiro [1.7K]2 years ago

7 0

Ratio of their bases = $$\frac{12}{10}$

Ratio of their altitudes = $$\frac{6}{5}$

<u>Step-by-step explanation:</u>

For first rectangle, it was given that

Base 1 = 12 inches

Altitude 1 = 6 inches

For the second rectangle, it was given that

Base 2 = 10 inches

Altitude 2 = 5 inches

Ratio of their bases is given by the ratio of the base of the first rectangle to the second one.

Ratio of their altitudes is given by the ratio of the altitude of the first rectangle to the altitude of the second rectangle.

Ratio of their bases = $$\frac{12}{10}$

Ratio of their altitudes = $$\frac{6}{5}$

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pav-90 [236]

The equality used is Subtraction property of equality

Option A is correct

Step-by-step explanation:

We need to identify which option best explains or justifies Step 1.

Step 1 is: $-c = ax^2 + bx$

The given equation is: $0 = ax^2 + bx + c$

To get the equation for step 1 we need to subtract c on both sides of equation i.e using subtraction property of equality

$0-c = ax^2 + bx + c-c$

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2 years ago

ABC and EDC are straight lines. EA is parallel to DB. EC = 8.1 cm. DC = 5.4 cm. DB = 2.6 cm. (a) Work out the length of AE. cm (

harkovskaia [24]

By applying the knowledge of similar triangles, the lengths of AE and AB are:

a. $\mathbf{AE = 3.9 $ cm}\\\\$

b. $\mathbf{AB = 2.05 $ cm} \\\\$

<em>See the image in the attachment for the referred diagram.</em>

<em />

The two triangles, triangle AEC and triangle BDC are similar triangles.
Therefore, the ratio of the corresponding sides of triangles AEC and BDC will be the same.

<em>This implies that</em>:

AC/BC = EC/DC = AE/DB

<em><u>Given:</u></em>

$EC = 8.1 $ cm\\\\DC = 5.4 $ cm\\\\DB = 2.6 cm\\\\AC = 6.15 $ cm$

<u>a. </u><u>Find the length of </u><u>AE</u><u>:</u>

EC/DC = AE/DB

Plug in the values

$\frac{8.1}{5.4} = \frac{AE}{2.6}$

Cross multiply

$5.4 \times AE = 8.1 \times 2.6\\\\5.4 \times AE = 21.06$

Divide both sides by 5.4

$AE = \frac{21.06}{5.4} = 3.9 $ cm$

<u>b. </u><u>Find the length of </u><u>AB:</u>

$AB = AC - BC$

AC = 6.15 cm

To find BC, use AC/BC = EC/DC.

Plug in the values

$\frac{6.15}{BC} = \frac{8.1}{5.4}$

Cross multiply

$BC \times 8.1 = 6.15 \times 5.4\\\\BC = \frac{6.15 \times 5.4}{8.1} \\\\BC = 4.1$

Thus:

$AB = AC - BC$

Substitute

$AB = 6.15 - 4.1\\\\AB = 2.05 $ cm$

Therefore, by applying the knowledge of similar triangles, the lengths of AE and AB are:

a. $\mathbf{AE = 3.9 $ cm}\\\\$

b. $\mathbf{AB = 2.05 $ cm} \\\\$

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2 years ago

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Verizon [17]

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2 years ago

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rewona [7]

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2 years ago

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