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kumpel [21]
3 years ago
5

Which statement is true about two angles that are complementary?

Mathematics
2 answers:
m_a_m_a [10]3 years ago
5 0
Complementary angles are two angles that total 90°, so yes, you are correct.

ANSWER: The answer is (B) the sum of the measures of the two angles is 90°.

Hope this helps! :)
Dmitry [639]3 years ago
4 0

Answer:

Step-by-step explanation:

the answer is b hope this helps

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I NEED HELP WITH THIS
fenix001 [56]

Answer:

(i think it is for q6 so) $6

Step-by-step explanation:

4.50÷3=1.50 (that's for 1 pound of fudge)

1.50×4=6

3 0
3 years ago
Solve by substitution-5x+4y=22 x - 3y = 0A) No solution.
zepelin [54]
We want to use substitution to solve
-5x + 4y = 22           (1)
 x - 3y = 0                (2)

From (2), obtain
x = 3y                      (3)
Substitute (3) into (1).
-5(3y) + 4y = 22
-15y + 4y = 22
-11y = 22
y = -2
From (3), obtain
x = 3y = 3*(-2) = -6

Answer: e. (-6, -2)
5 0
3 years ago
Please help me solve this math problem
gladu [14]
Point A is exactly in the middle...it is halfway between 0 and 1...so it is 1/2 or 0.5
6 0
3 years ago
14a²b<br> 7a²b<br> =<br> Simplify
lidiya [134]

Step-by-step explanation:

if14a^2b/7a^2b answer is 2

and if the sign is addition then the answer is21a^2b if subtraction answer is7a^2b

4 0
3 years ago
Consider the following division of polynomials.
Bond [772]

x^4=x^2\cdot x^2. Multiplying the denominator by x^2 gives

x^2(x^2+2x+8)=x^4+2x^3+8x^2

Subtracting this from the numerator gives a remainder of

(x^4+x^3+7x^2-6x+8)-(x^4+2x^3+8x^2)=-x^3-x^2-6x+8

-x^3=-x\cdot x^2. Multiplying the denominator by -x gives

-x(x^2+2x+8)=-x^3-2x^2-8x

and subtracting this from the previous remainder gives a new remainder of

(-x^3-x^2-6x+8)-(-x^3-2x^2-8x)=x^2+2x+8

This last remainder is exactly the same as the denominator, so x^2+2x+8 divides through it exactly and leaves us with 1.

What we showed here is that

\dfrac{x^4+x^3+7x^2-6x+8}{x^2+2x+8}=x^2-\dfrac{x^3+x^2+6x-8}{x^2+2x+8}

=x^2-x+\dfrac{x^2+2x+8}{x^2+2x+8}

=x^2-x+1

and this last expression is the quotient.

To verify this solution, we can simply multiply this by the original denominator:

(x^2+2x+8)(x^2-x+1)=x^2(x^2-x+1)+2x(x^2-x+1)+8(x^2-x+1)

=(x^4-x^3+x^2)+(2x^3-2x^2+2x)+(8x^2-8x+8)

=x^4+x^3+7x^2-6x+8

which matches the original numerator.

3 0
3 years ago
Read 2 more answers
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