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nataly862011 [7]
3 years ago
12

a train leaves a station and travels north at a speed of 105mph. two hours later, a second train leaves on a parallel track and

travels north at 135mph. how far from the station will they meet
Mathematics
1 answer:
meriva3 years ago
8 0
Let the second train catch up after x hours 

<span>Distance = speed X time </span>

<span>135x = 105 ( 2 + x) </span>

<span>135x = 210 + 105x </span>

<span>30x = 210 </span>

<span>x = 7 hours (after 2nd train has started ) </span>
<span>ANSWER 7 X 135 = 945 miles from the starting point </span>

<span>CHECK </span>
<span>7 X 135 = 945 miles </span>

<span>9 X 105 = 945 miles</span>
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Answer:

a) attached below

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Step-by-step explanation:

A) write down the game in matrix form

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     N = exit at the end of the next quarter

matrix is attached below

B) weakly dominated strategies is ( T,T )

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D ) Find the unique mixed-strategy Nash equilibrium

The mixed-strategy Nash equilibrium for Firm 1 = ( 1/3 , 0, 2/3 )

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Assume that P is the probability of firm 1 exiting immediately ( E )

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Answer:

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Step-by-step explanation:

z(5z²-80) ÷ 5z(z+4) = z-4

Step-by-step explanation:

Given: z(5z²-80) ÷ 5z(z+4)

Calculation:

First we factor numerator z(5z²-80)

Take out 5 from 5z²-80 and we get 5z(z²-16)

Now we factor 16 = 4²

5z(z²-4²)

Using formula, (a²- b²)=(a+b)(a-b)

5z(z²- 4²)⇒5z(z+4)(z-4)

Simplified fraction

5z(z+4)(z-4) ÷ 5z(z+4)

Cancel like factor from numerator and denominator

⇒ z-4

Thus, z(5z²-80) ÷ 5z(z+4) = z-4

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