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trasher [3.6K]
3 years ago
12

find two consecutive odd numbers such that the sum of the larger number and twice the smaller number is 27 less then four times

the smaller number.
Mathematics
1 answer:
soldier1979 [14.2K]3 years ago
4 0

N is an odd integer

The Next Larger is N+2

N+2 + 2N = -27 + 4N

3N + 2 = 4N - 27

0 = 4N - 27 - 3N - 2

0 = N - 29

N = 29

They are 29 and 31.

31 + 2(29) = 4(29) - 27

31 + 58 = 89 = 116 - 27  yes it works

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Find two numbers between 3.456 and 3.457
kow [346]

Answer:

3.4567

3.4568

Step-by-step explanation:

We need to find a number between 3.456 and 3.457. In order to do so, we need to dive deeper into the decimal to get numbers in-between.

We need to dive to the ten-thousandths place to get numbers between the two.

6 0
3 years ago
PLEASE HELP I WILL GIVE BRAINLIEST!! PLEASE DONT PUT AN ABSURD ANSWER!<br> HURRY!!!
tiny-mole [99]
My answer is A. Hands down A.
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2 years ago
tarik starts a morning walk at 7:00 am. his distance, in miles, to the nearby grocery store after x hours is f(x)
Grace [21]

Total distance walked by Tarik is 0.75 miles according to the given equation.

What is equation?

In arithmetic, an equation could be a formula that expresses the equality of 2 expressions, by connecting them with the sign =.

Main body:

Given that

The expression that represents the Tarik's distance is

=>  f(x) = 3∣x−0.5∣

And also given that at 7.15 am he is some distance away from the store

Let Tarik is 'a' miles away from the store at 7.15 am

The time taken to walk 'a' miles = 7.15 - 7.00 = 15 minutes

As we know 60 minutes = 1 hr

=> 15 minutes = 15/60 = 0.25 hrs  

The given expression to find the Distance is

f(x) = 3 ∣x − 0.5∣    where x is number of hours

At x = 0.25

f(0.25) = 3 |0.25 - 0.5|

= 3 |- 0.25|

= 0.75 miles

Therefore,Tarik is 0.75 miles away from the store.

To know more about equation , visit:

brainly.com/question/22688504

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8 0
1 year ago
Please help fast i need help ​
Nutka1998 [239]

Answer:

omg

I

1. 3×3×3×3 = 81

2. 2²a³

3. (-5)³ (-5×-5×-5) = -125

4. 1

5. a^m-n

II

1. 1.6807× 10⁴

2. (7×7×7) × (2×2×2×2×2×2) = 21952

3. 32²

4. 2187

5. 803025

3 0
2 years ago
Read 2 more answers
How do the values in Pascal’s triangle connect to the coefficients?
damaskus [11]

Explanation:

Each row in Pascal's triangle is a listing of the values of nCk = n!/(k!(n-k)!) for some fixed n and k in the range 0 to n. nCk is <em>the number of combinations of n things taken k at a time</em>.

If you consider what happens when you multiply out the product (a +b)^n, you can see where the coefficients nCk come from. For example, consider the cube ...

  (a +b)^3 = (a +b)(a +b)(a +b)

The highest-degree "a" term will be a^3, the result of multiplying together the first terms of each of the binomials.

The term a^b will have a coefficient that reflects the sum of all the ways you can get a^b by multiplying different combinations of the terms. Here they are ...

  • (a +_)(a +_)(_ +b) = a·a·b = a^2b
  • (a +_)(_ +b)(a +_) = a·b·a = a^2b
  • (_ +b)(a +_)(a +_) = b·a·a = a^2b

Adding these three products together gives 3a^2b, the second term of the expansion.

For this cubic, the third term of the expansion is the sum of the ways you can get ab^2. It is essentially what is shown above, but with "a" and "b" swapped. Hence, there are 3 combinations, and the total is 3ab^2.

Of course, there is only one way to get b^3.

So the expansion of the cube (a+b)^3 is ...

  (a +b)^3 = a^3 + 3a^2b +3ab^2 +b^3 . . . . . with coefficients 1, 3, 3, 1 matching the 4th row of Pascal's triangle.

__

In short, the values in Pascal's triangle are the values of the number of combinations of n things taken k at a time. The coefficients of a binomial expansion are also the number of combinations of n things taken k at a time. Each term of the expansion of (a+b)^n is of the form (nCk)·a^(n-k)·b^k for k =0 to n.

6 0
3 years ago
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