5x3-4x2-20x+16=0 Three solutions were found : x = 4/5 = 0.800 x = 2 x = -2Reformatting the input :Changes made to your input should not affect the solution:
(1): "x2" was replaced by "x^2". 1 more similar replacement(s).
Step by step solution :Step 1 :Equation at the end of step 1 : (((5 • (x3)) - 22x2) - 20x) + 16 = 0 Step 2 :Equation at the end of step 2 : ((5x3 - 22x2) - 20x) + 16 = 0 Step 3 :Checking for a perfect cube : 3.1 5x3-4x2-20x+16 is not a perfect cube
Trying to factor by pulling out : 3.2 Factoring: 5x3-4x2-20x+16
Thoughtfully split the expression at hand into groups, each group having two terms :
Group 1: 5x3+16 Group 2: -4x2-20x
Pull out from each group separately :
Group 1: (5x3+16) • (1)Group 2: (x+5) • (-4x)
I hope it helps
-5/12 x (6/5 x 1/3) x 9/2 = (-5/12 x 6/5) x (1/3 x 9/2) as said equation correlates with the following formula: (a x b) x c = a x (b x c) where the way you group three or more numbers when adding or multiplying does not change their overall sum or product. Hope this helped! :)
Divide the numerator by denominator
23÷4=5 (3/4)
Answer:
Tuesday march 5th she will vacuum her floor. Friday march 8th she will clean her bathroom.
Step-by-step explanation:
