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borishaifa [10]
2 years ago
10

lim with x yields infinity below left parenthesis fraction numerator t left parenthesis 2 over denominator 2 end fraction s to t

he power of 5 less or equal than fraction numerator 4 s plus 4 over denominator 1 plus-or-minus 1 end fraction division sign
Mathematics
2 answers:
Bas_tet [7]2 years ago
5 0

Answer:

do the math with a calculator

Step-by-step explanation:

Aleksandr [31]2 years ago
3 0

Answer:

The vertical asymptotes are x=3 and x=-3. The horizontal asymptote is y=20.

Step-by-step explanation:

The given function is

Equate the denominator equal to 0, to find the vertical asymptotes.

Add 9 on both sides.

Taking square root on both sides.

Therefore the vertical asymptotes are x=3 and x=-3.

The given function can be written as

Degree of numerator and denominator are same.If degree of numerator and denominator are same, then horizontal asymptote is

Therefore the horizontal asymptote is y=20.

Step-by-step explanation:

Hope this helps:)

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An equation of a parabola with its vertex at (-3,2) and focus at (-3,-1) written in general equation form
german
<span> we have that
standard form of equation for parabola:
 (x-h)^2=-4p(y-k)
(h,k) --------->being the (x,y) coordinates of the vertex.
Parabola opens downwards because focus is below vertex on the axis of symmetry.
For given problem:
</span><span>vertex: (-3,2)
axis of symmetry: x=-3
p=distance from vertex to focus on the axis of symmetry=2-(-1)=3
4p=12
Directrix: y=2+p=5
Equation:
(x+3)^2=-12(y-2)

the answer is </span>(x+3)^2=-12(y-2)
5 0
2 years ago
I’m trying to correct this problem but I don’t know how can someone help me
BartSMP [9]

Remark

It is not a straight line distance from the park to the mall. None of the answers give you that result. And if you know what displacement is, none of the answers are really displacement either. The distance is sort of a "as the crow flies." distance. There's a stop off in the middle of town.

Method

You need to use the Pythagorean Formula twice -- once from the park to the city Center and once from the city center to the mall.

Distance from the Park to the city center.

a = 3   [distance east]

b = 4  [distance south]

c = ??

c^2 = 3^2 + 4^2        Take the square root of both sides.

c = sqrt(3^2 + 4^2)

c = sqrt(9 + 16)          Add

c = sqrt(25)

c = 5

So the distance from the park to the city center is 5 miles

Distance from City center to the mall

a = 2 miles [distance east]

b = 2 miles [distance north]

c = ??

c^2 = a^2 + b^2   Substitute

c^2 = 2^2 + 2^2   Expand this.

c^2 = 4 + 4

c^2 = 8             Take the square root of both sides.

sqrt(c^2) = sqrt(8)

c = sqrt(8)          This is the result

c = 2.8

Answer

Total distance = 5 + 2.8 = 7.8

6 0
3 years ago
What is the common angle of triangle PQT and triangle RSQ?
Elodia [21]

we know that

The internal angles of the triangle PQT are

Angles

TPQ

PQT=SQR

QTP

The internal angles of the triangle RSQ are

Angles

SRQ

SQR=PQT

QSR

therefore

the answer is

angle\ PQT

6 0
3 years ago
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Please help me I’m not good at this
Pepsi [2]
Multiply the Day with 9

1 x 9 = 9 (True)
2 x 9 = 18
3 x 9 = 27
4 x 9 = 36
5 x 9 = 45 
6 x 9 = 54
7 x 9 = 63


63 minutes is your answer

hope this helps
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3 years ago
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Find <br><br>dr/ds if r = s³/2 +1<br>​
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Answer:

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Step-by-step explanation:

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