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netineya [11]
3 years ago
11

How do you know a relationship is proportional

Mathematics
1 answer:
Nadya [2.5K]3 years ago
4 0

Answer:

One way to see if two ratios are proportional is to write them as fractions and then reduce them. If the reduced fractions are the same, your ratios are proportional

Ratios are proportional if they represent the same relationship.

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The formula for volume of a prism is V=Bh. What does the B stand for
Marizza181 [45]

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Area of the base

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Please help ASAP! <br> X= <br><br> A) 4<br> B) 7<br> C) 9
melisa1 [442]

Answer:

C) x = 9

Step-by-step explanation:

When two segments intersect in a circle like so, the product of the two parts of one segment will be equal to the product of the two parts of the other segment.

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The perimeter of equilateral triangle ABC is 81/3 centimeters, find the length of the radius and apothem.
MAXImum [283]

There is a typo error, the perimeter of equilateral triangle ABC is 81/√3 centimeters.

Answer:

Radius = OB= 27 cm

Apothem = 13.5 cm

A diagram is attached for reference.

Step-by-step explanation:

Given,

The perimeter of equilateral triangle ABC is 81/√3 centimeters.

Substituting this in the formula of perimeter of equilateral triangle =3\times\ side

3\times\ side =[tex]81\sqrt{3}

Side = \frac{81\sqrt{3} }{3} =27\sqrt{3} \ cm

Thus from the diagram , Side AB=BC=AC= 27\sqrt{3} \ cm

We know each angle of an equilateral triangle is 60°.

From the diagram, OB is an angle bisector.

Thus \angle OBC = 30°

Apothem is the line segment from the mid point of any side to the center the equilateral triangle.

Therefore considering ΔOBE, and applying tan function.

tan\theta =\frac{perpendicular}{base} \\tan\theta=\frac{OE}{BE} \\tan\theta=\frac{OE}{\frac{27\sqrt{3}}{2}  } \\tan30\times {\frac{27\sqrt{3} }{2} }= OE\\\frac{1}{\sqrt{3} } \times\frac{27\sqrt{3} }{2} =OE\\

Thus ,apothem  OE= 13.5 cm

Now for radius,

We consider ΔOBE

cos\theta=\frac{base}{hypotenuse} \\cos30= \frac{BE}{OB} \\Cos30 = \frac{\frac{27\sqrt{3} }{2}}{OB}  \\OB= \frac{\frac{27\sqrt{3} }{2}}{cos30} \\OB= \frac{\frac{27\sqrt{3} }{2}}{\frac{\sqrt{3} }{2} } \\OB =27 \ cm

Thus for

Perimeter of equilateral triangle ABC is 81/√3 centimeters,

The radius of equilateral triangle ABC is 27 cm

The apothem of equilateral triangle ABC is 13.5 cm

4 0
3 years ago
Make U the subject of the formula <br> D = ut + kt2
natali 33 [55]

Remark

I'm going to interpret this equation as

D = ut + kt²  The only difference is the 2.

Solution

Subtract kt² from both sides.

D - kt² = ut   Now divide by u on both sides.

\dfrac{D - kt^2}{t} = \dfrac{ut}{t}

The t's cancel out. on the right.  You are left with u on the right.

\dfrac{D - kt^2}{t} =\text{u}


6 0
3 years ago
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