An exterior angle of a triangle is equal to the sum of the opposite interior angles.
⇢∠V + ∠T = ∠x
⇢53° + 103° = 156°
⇢∠VUX = 156°
Hence , option b is the correct answer.
Answer:
Using the formula, write in standard form.
=
−
5
h
−
2
Step-by-step explanation:
Y1 is the simplest parabola. Its vertex is at (0,0) and it passes thru (2,4). This is enough info to conclude that y1 = x^2.
y4, the lower red graph, is a bit more of a challenge. We can easily identify its vertex, which is (-4,0), and several points on the grah, such as (2,-3).
Let's try this: assume that the general equation for a parabola is
y-k = a(x-h)^2, where (h,k) is the vertex. Subst. the known values,
-3-(-4) = a(2-0)^2. Then 1 = a(2)^2, or 1 = 4a, or a = 1/4.
The equation of parabola y4 is y+4 = (1/4)x^2
Or you could elim. the fraction and write the eqn as 4y+16=x^2, or
4y = x^2-16, or y = (1/4)x - 4. Take your pick! Hope this helps you find "a" for the other parabolas.
Answer:
<em>y - 7 = 1 (x-5)</em>
Step-by-step explanation:
The point slope equation of a line is expressed as;
y - y0 = m(x-x0)
m is the slope
(x0, y0) is the point on the line
Given the following
m = 1
(x0, y0) = (5, 7)
Substitute into the formula
y - 7 = 1 (x - 5)
y - 7 = x -5
y = x - 5 + 7
y = x + 2
<em>Hence the point slope equation of the line is y - 7 = 1 (x-5)</em>
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Answer:
Explanation:
In the first example the division results in a radical, not a polynomial.
The remaining examples are not counter-examples (they do result in a polynomial)
