Set x as adult tickets.
Set y as children's tickets.
x + y = 15
30x + 20y = 270
Solve for x in the first equation.
x + y = 15
x = 15 - y
Plug this into the second equation.
30x + 20y = 270
30(15 - y) + 20y = 270
450 - 30y + 20y = 270
450 - 10y = 270
-10y = -180
y = 18
If there is 18 childrens tickets, there should be -3 adult tickets.
This is impossible, and this impossible answer occured because the question is written wrong.
There are a total of 15 tickets
The smallest costing ticket is the childrens ticket, which costs 20$.
If he only bought children tickets, this would be 20x15 which is 300$.
300$ is over 270$, which makes the question impossible.
It is possible
Group 1 : 684 divided by 36 = 19$
Group 2 : 456 divided by 24 = 19$
Therefore, both groups 1 and 2 charge $19 for each ticket
Answer:
h=7ft
Step-by-step explanation:
sinФ=opposite/hypotenuse
sin45°=5/h
0.71=5/h
multiply via by h
0.71h=(5/h)h
h cancel h it remains 5
0.71h=5
divide through by 0.71
0.71h/0.71=5/0.71
h=7.04ft
h=7ft approximately
10 1/2 bags of seed. 3×3 1/2
